Physics Oscillations part 13 (Accelaration in Simple harmonic Motion) CBSE class 11

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Physics Oscillations part 13 (Accelaration in Simple harmonic Motion) CBSE class 11
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Many of you are asking how is a = w^2.r
here it is,
a = v^2/r,
v^2 = (w.r)^2
(w.r)^2/r = w^2.r
Hope that helps!

krishnanegi
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how a = -w^2A is right formula if a(t) = -w^2x(t) so why not it becomes a(t)=w^2x(t).AND how how the diiferentiation of a(t) becomes -Aw^2 Cos(wt+Φ) and why not it becomes -ACos(wt+Φ)? I NEED HELP EXAM PLEASE

harryshawla
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mam the given video is quite confusing

tabanisyes
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guys read ur cert textbook page 343
hop u will get it

juhainahussain
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mam i have a doubt
it is explained in the video that : a=-w^2*A
and the equation of acceleration in SHM is given as : a(t)=-a*cosθ
on substituting the value of a in the equation of a(t) why don't the minuses cancel each other and become : a(t)=w^2*A * cosθ

gomathisankar
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the mean position a particular point only how could that be the centre?

hifzurrahman
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As shown in video a(t) is equal to -w^2x then how is acc directly proportional to x???? There's a negative sign also, why we r not considering that?

ShreyaRajBEC
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how the centre can be the mean? maam plzz mail me

hifzurrahman
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can u pls give the alternative metherd

sarang