Prove: `(sectheta+costheta)(sectheta-costheta)=tan^2theta+sin^2theta`

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Prove: `(sectheta+costheta)(sectheta-costheta)=tan^2theta+sin^2theta`
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Easy method for this ques is
sec ^2 theta - cos ^ 2
( 1 + tan ^2 theta ) - ( 1 - sin^2 theta )
1 + tan ^2 theta - 1 + sin^2 theta
+1 and -1 is cancel then the remaining part is tan^2 theta + sin^ theta .
Proved

shalini
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Sec theta square - cos theta square
1-tan square theta -1- sin square theta
-tan square theta -sin square theta
Minus minus cancel
So answer is tan square theta + sin square theta

weven
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Sir the way you are proving its to complicated. unable to understand 🥺😢😢

Mr._P_YTube