LeetCode Problem: Product of Array Except Self | Optimized C# Solution Explained

Here's my solution to the LeetCode Problem 238: Product of Array Except Self, implemented in C#. 🚀

💡 Problem Overview:
The challenge is to calculate the product of all elements in an array except the current one for each index, without using division extensively and while keeping the time complexity O(n). This intuitive solution handles edge cases like zeros efficiently and provides a clear approach to solve this problem.

✅ What You'll Learn in This Video:

How to calculate the product of an array while addressing edge cases (like zeros).
Optimized implementation with minimal extra space.
Clean and efficient C# code explained step-by-step.
🔔 Highlights of This Solution:

Time Complexity: O(n), as the array is traversed just once.
Space Complexity: O(1) (excluding the result array), as it uses only a few variables for computation.
💡 Whether you're practicing array-based problems, exploring efficient algorithms, or preparing for coding interviews, this tutorial covers the essentials in the simplest way possible.

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