Interpreting Motion Graphically (1 of 4: Direction of movement)

[angelglez.]

Congrats!! For your first million subscribers

[arjundhingra]

one MILLION subs Congratulation Mr. Woo love all your video content and, of course, your way of understanding and teaching 😀

Great, as usual. And, I'd like to say that you, Eddie Woo, deserves a Googolplex of subscribers... :-)

[uditagarwal]

Sir please teach Algebra and number theory also. I am not able to fond your old vidoes

[ninjasuperbawesome]

Would you be uploading any videos on trigonometric functions(not just inverse trigonometry)? I really enjoyed your calculus lessons; I hope to see you cover more topics with your flawlessly flamboyant teaching style!

[devanprajekta]

What software do you use to draw the math object such as graph, rectangle, cube, etc?

[AngelinaCruz]

I am looking at the height, indicating force; width, indicating time; and direction! #Key #Elements

[Bharath.R]

Sir you have nice concept understanding skill please make a video on concept understanding on mathematics, correctly😥,
please ha

[沈博智-xy]

I got bored and tried to find the exact cubic equation (and tried to answer f) part i) exactly)
We know the points are (0, 0), (3, 8), (6, 4) and (9, 0) where (9, 0) is a double root.
Using this with x = at^3 + bt^2 + ct + d, we can create simultaneous equations with those points and find
a = 2/27, b = -4/3, c = 6, d = 0
we can find exactly the velocity function and the acceleration function.
v = 2t^2/9 -8t/3 + 6 ($\dot{x} = \frac{2t^2}{9} - \frac{8t}{3} + 6$)
a = 4t/9 - 8/3 ($\ddot{x} = \frac{4t}{9} - \frac{8}{3}$)
Using this, the velocity at t = 2 seconds is 14/9 metres per second
Using symmetry, this also happens at t = 10 seconds

Also at t = 2, the displacement at t = 2 is
x = 2(2)^3/27 -4(2)^2/3 + 6(2) = 196/27
So the displacement at t = 2 is 196/27 metres or 7 and 7 twenty sevenths metres
(displacement = $\frac{196}{27}$ m $\lor$ $7\frac{7}{27}$ m $\lor$ $7.\dot{2}5\dot{9}$)

If we adjust the equation to:
x = 2t^3/27 -4t^2/3 + 6t - 196/27 ($x = \frac{2t^3}{27} -\frac{4t^2}{3} + 6t - \frac{196}{27}$)
then t = 2 becomes a root... we can now use newton's approximation method to find roots.
If we start at t_1 = 4 as an estimate...
We get the exact root at t_4 =

or as a mixed numeral:

so the answer to f) part i) exactly would be at t = seconds

[Bharath.R]

I have a doubt,
For which grade you will take class🥺

[mrkitty]

Excellent explanation. Off topic but is anyone else seeing accounts in the comments from so called catfish women? Hopefully nerds are smart enough to understand not to catfish.

[Bharath.R]

I have a doubt,
For which grade you will take class🥺