Projection of Points Problem 3

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[a.v]

Note. You fullfill every engineers request and make life easy... Thanks sir

[yash-hcpi]

Sir I thought I was going to fail Ed but now I'm gonna top them thnx to you 😊

[sruthihasini]

thank u sir i have my xam by tomorrow i have listened all ur viedoes now i have understood u alot sir

[KS-enhn]

Sir
1. B was behind VP, hence it could have been either in II or in III quadrant. Then why did we assume it so?
2. 45° angle was made wrt XY line. So for other generalised cases, we must draw an angle of 90-theta right (with a as vertex)?

[NikhilKumar-xvzl]

I have problem in this topic but you solve my problem.. Thanx

[saleemshaik]

Thank you so much for explain me.my dought is clean thanks boss...

[SravanKumar-rgdg]

Sir why ur taking 30mm below the xy line

[ANGRYONEFF]

Sir how did you consider point B in sec quadrant sir ?

[rajeswarianisetti]

Sir is there any another model for this problem?

[tanshuarora]

sir thanks a lot for making these videos

[amalashok]

Gud explanation sir but I m getting only 40mm distance between b and b'

[famousmagicintheclassmoham]

hllo sir i have a doubt why we are using only smal letters instead capital letters as because in ur question the projectors in caps then y are u using small letters pls reply

[sairamjatoth]

Thank u sir for giving very simply solutions

[RAJ-evgm]

This is not objective approch oriented... You should solve it with mathematics too...

[bhatdanish]

Sir plx upload the videos of md plxxx plxxx plxxx