find value of sin45, cos45, tan45 Geometrically I class 10 X I trigonometry I cbse I ncert I icse

find value of sin45 cos45 tan45 Geometrically I class 10 X I trigonometry I cbse I ncert I icse by DEEPAK MITTAL.
CHAPTER: TRIGONOMETRY

Trigonometry is a branch of mathematics dealing with relations involving lengths and angles of triangles. It can, in a simpler manner, be called the study of triangles. Here, we have discussed the
Trigonometry Class 10:
Trigonometry is a branch of mathematics dealing with relations involving lengths and angles of triangles. It can, in a simpler manner, be called the study of triangles. The angles are either measured in degrees or radians. We need to look into trigonometric formulae, ratios, functions etc. in order to grasp the concept completely. Here, we have discussed the basic concepts of Trigonometry Class 10.

T The types of triangles can be divided on the basis of length and angle.
On the basis of length, there are three types: scalene (all the sides and angles are different), isosceles (2 sides and 2 angles are equal) and equilateral triangle (all the sides and angles are equal). On the basis of angles, it is again divided into three kinds: acute-angled triangle (all angles are less than 90 degrees), right-angled triangle (one angle is equal to 90 degrees) and obtuse-angled triangle (one angle is greater than 90 degree).

The sum of the three angles of the triangle equals 180 degree
The sum of the length of two sides of a triangle is greater than the third side whereas the difference between the lengths of two sides is less than the third side’s length.
The longest side is equal to the largest angle and vice versa.
Area of the triangle = ½ x base x height
According to Heron’s formula, Area of the triangle is √s(s−a)(s−b)(s−c), where s is the semi perimeter and is calculated by the following formula: ½ (a + b + c) where a, b, c, are the sides of the triangle.
Sine, Cosine and Tangent
According to the theorem

a2 + b2 = c2
Sin ² θ + Cos ² θ = 1
Tan 2 θ + 1 = Sec2 θ
Cot2 θ + 1 = Cosec2 θ
Sin 2θ = 2 sin θ cos θ
Cos 2θ = cos² θ – sin² θ
Tan 2θ = 2 tan θ / (1 – tan² θ)
Cot 2θ = (cot² θ – 1) / 2 cot θ
Congruence of a triangle
If a triangle is such, that when it is placed on the other, can be superimposed on it, it is said to be a set of congruent triangles. If the sides and angles of two triangles are the same, then they are called congruent triangles. It is denoted by the sign ≅

There are different rules for congruency. They are:

SSS (Side Side Side) – If the three sides of triangle 1 are equal to the corresponding sides of triangle 2, they are said to be congruent by the SSS property.
SAS (Side Angle Side) – If any two sides of a triangle 1 and their included angle are equal to the corresponding two sides and the respective included angle of triangle 2, they are said to be congruent by the SAS property.
ASA (Angle Side Angle) – If any two angles and the included side of triangle 1 are equal to the corresponding two angles and the included side of triangle 2, they are said to be congruent by the ASA property.
RHS (Right-Angle Hypotenuse Side) – If a side and hypotenuse of a right triangle 1 is equal to the corresponding side and hypotenuse of a right triangle 2, then they are said to be congruent by the RHS property.
Similar Triangles
Triangles with same angles and different length of sides are called similar triangles. They are denoted by ~ symbol. Hence, for two triangles to be similar the conditions that need to be met are:

These two triangles are similar if and only if:

∠A = ∠X, ∠B = ∠Y and ∠C = ∠Z
AB / XY = BC / YZ = AC / XZ
There are different rules for the similarity of a triangle. They are:
AAA
If any two angles of triangle 1 are equal to corresponding angles of triangle 2, they are similar triangles by the AAA property.
SAS
If two sides of triangle 1 is in the same ratio of the two angles of triangle 2 and the angle included by the 2 sides are equal in both the triangle, it is said to be similar by the SAS property.

SSS
If the three sides of triangle 1 are in proportion to the three sides of triangle 2 they are said to be similar by SSS property.

Some theorems on similarity
The ratio of area of two triangles is in proportion with the squares of ratio of their sides, if two triangles are similar. In triangle ABC and triangle PQR, if they are similar, then
Area of ABC / Area of PQR = (AB/PQ)2 = (BC/QR)2 = (CA/RP)2

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Sir jab hamko 45 degree prove Karna Ho to right angle triangle lena hai