MA8351| DISCRETE MATHEMATICS| UNIT-1| VIDEO-19| THEORY OF INFERENCE| INDIRECT METHOD| PROBLEM-5

preview_player
Показать описание

Рекомендации по теме
Комментарии
Автор

Tnx mam... My clg la clear ah solitharala mam😩😩... But, nega sollurathu nalla understand aguthu 🥰🥰🥰.... Tnx mam

viperraghu
Автор

I'm getting 7s in 9th step(as final step) is this correct? is there any chance tht I can prove this as contradiction since I've got S in 7th step which is true statement and got 7S in 9th step which is opposite to the 7th step(s)..plzz somebody answer???

jerrygeorgejoshi
Автор

Mam aathu pathila step 12 la

11) 7Q
12) P -> Q RULE P
13) 7Q -> 7P RULE T ( P -> Q => 7Q -> 7P ) BY 12
14) 7P RULE T (P, P -> Q => Q) BY 11 & 13

intha mathiri podalama mam, neega tha sonnika necessary na again use pannalam nu .

windowstechnology
Автор

P->Q ah Q->P ah consider panalama mam ..
bcoz P->Q, Q->R = P->R
suppose enakku statements P->Q, R->Q nu irutha naa P->Q nu potukalama

leoaruna
Автор

First stmt ah assume panathuku aprmm, remaining stmt ah entha order la nalum eluthlama mam ? Ethachu stmt ah use panama kooda irukalama ?
3rd qn answer konjam share panunga mam

arunsuresh
Автор

S->~Q, S v R, ~R, ~P<->Q =>~P
Mam indha sum konja different ahh irukku..neenga solli tharla ..konja idhuku mattu ans solve panni kudunga mam

Faiz-dnxt
Автор

Mam third answer doubt mam plz send tht notes mam 🥲???

Mines_bot