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  1. Naresh Gupta
  2. string
  3. prefix
  4. common
  5. longest
  6. leetcode
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Комментарии
Автор

Thanks for very understandable and clean code.

SahilSingh-pcvd
Автор

IN PYTHON
s=["flow", "flew", "flower"]
k=s[0]
flag=0
a=""
for x in range(len(k)):
for j in s[1:]:
if k[x]!=j[x]:
flag=1
else:
a=""+k[x]
if flag==1:
break
else:
print(a, end="")

aadhi_dinesh