LeetCode 108. Convert Sorted Array to Binary Search Tree - Interview Prep Ep 71

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Solutions explained:
We'll find the middle node in the sorted array to form the current root node, and then keep doing so recursively to build its left and right subtrees.

Time complexity: O(n)
Space complexity: O(n)

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Best Ever explanation. Please add more Medium and Hard Problems from leetcode. Thanks for the effort and hard work.

ChandraShekhar-bycd

Fisher you are the best. Thanks for your video!

yxs

Great explanation. Subscribed. By the way How do you see Messenger and whatapp on the sidebar? Is it extension?

raymondc

Here start+end/2 may overflow better would be to use start + (end-start)/2

ChandraShekhar-bycd

Would this problem have an iterative counterpart? The recursive version seems quite obvious to me but I'm not sure how I would take advantage of a stack/queue to do this iteratively.

ryancodrai

Didn’t understood, what is the need of base condition and how it works? Mean to say end is always gonna be greater than start which is always 0

nishargshah

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