Electrical Engineering: Ch 4: Circuit Theorems (19 of 32) Norton's Theorem Example 1

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In this video I will find the Norton equivalent circuit of a circuit with a 2amp source with 8V voltage source and 2 resistors.

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You are an excellent teacher. No one can teach all these topics better. I love the way you present these complex techniques simply. I've been following all your videos. I appreciate you. I want you to minimize the way the board is covered during lectures. I don't know how you can do that but I want the board to be visible at all times.

adeyemoja
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Perfect! Among my favorite online lectures! Thank you!

Jazzid
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I think at 2:40 it would be easier to transform the 8V and 8 ohm to a 1 amp parallel to 8 ohm. Than there would be only one current source of 3 amp!

zyctc
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@1:38 you say the Norton resistance is the "resistance between A and B"... WHY?. If the circuit is open between A and B the resistance is infinity.

Festus
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Hey Michel, I really appreciate your lectures, and have been watching them for a little over a year now. I was wondering, when you disconnected a current source and replaced it with an open source, what if there happened to be a resistor that ceased to allow current to run through it? How would that affect finding Rth? Thanks!

natethegreatest
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where was I to find a good teacher like you😭😭😭

promisechitsanzo
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So well presented. Thank you so much.

ladyphoenix
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I am having a hard time understanding why the I1 is equal to 2 Amps. i get that there is a current source there that says 2 amps but what about the 8 ohm resistor and 8v voltage source?

Fadic
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Why did we add the 16ohm and 8 ohm resistor if they were in parallel?

GroovePG
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Out of curiosity, if we had a wire which began between the 16 Ohm resistor and the end-point A which ran down and connected to the end-point B branch, then the 8 Ohm and 16 Ohm resistors would be in parallel, correct? This seems to be something a lot of beginners, including myself, struggle with. There are so many definitions of parallel resistance that seem inconsistent. I usually go by "if the current splits between multiple resistors and end up back on the same branch then they are in parallel".

ReagueOfRegends
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Hi Michel, wondering what will be the value of Load R., I think you did not find that...

teamstudent
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why does current I1 flow through only 8 ohm resistance, but not through 16ohm? sir please explain...

lintugogoi
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How do you know I-1 of the Mesh Analysis is equal to 2 Amps? It does not appear to account for the I-2 traveling in the opposite direction through the 8 V and 8 R elements. Someone please clarify this point for me.

gabrieldennery
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just curios what would be the Rth if there was another resistor after the 2A

koko-ozjf
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A video on Thermodynamik, Gas - Dampf. Feuchte Luft is needed. Best Regards KQKR Kristian

kristiankristiansen
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im so confuse . at lesson 16, we have the same situation by they are parallel. why are these resistor are in series now ? ???

theson
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Please sir how did the voltage source(8v) goes to zero? I’m confused

emmanuelapuamadi
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Great explanations!
But I have a question: when you are writing the equation in the loop 2, doesn't the equation have to be 8 + (8)(i2 - i1) + 16(i2) = 0 which would give a current of 1/3 Amp

ghassanarnouk
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In this case, can we use Thevenin theorem?

quratulain
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????If We assume RL is 1ohm
Than equation Must be IL=(1/1+24)*1

jacobnatalinogomes
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