Projectile + Vertical Motion + Collision = Namo Sir’s Birthday Challenge ❤️🔥 Answer in Comment

[kaulnamo]

I think you should get u = 10.30 m/s - Calculated this mentally- Confirm in comments what you got ❤

[ronit]

When jee aspirants becomes tourist guide 😅😅...

[yashpratapsingh-fish]

Mitochondria is power house of cell 😂
Hypothalamus is master of master gland 😂😂

[shradhalala]

10.3 got it 💀I hope neet mein na aaye aise sawal.

[FouziyaKhan-yj]

Ans 10 m/s. First find t by √2h/g and then use projectile formula of height. H= u² sin²theta/2g

[jennymarx]

For height, time = √2h/g
G =10
= √2*5/10
=√1 =1

From base to top = t = 1
Therefore, from base to top to base = 2t = 2

Lets solve vertical and horizontal separately,

For vertical, from base to top,
= U = ?, v=0, g=10, t=1 (bcoz for half cycle t=1)
=> V-u = -gt
-u = -g×1
U = 10 (for vertical)

Horizontal = full cycle => t=2
U=?, distance=2.5, t=2
U=dist/t
U= 2.5/2 = 1.25


Total velocity= √v(horizontal)²+v(vertical)²

=√10²+1.25²
== Approximately 10.2!

[rahulkumar]

U will definitely crack jee advanced bro

[RahulKumar-qdty]

If there is elastic collision then how it's direction of velocity change if this feel jark in tangential direction then how we calculate work done by jark

[Mr.AIAnukalp]

If we take g 9.8 then answer is root 98 if we take 10 then ans is 10 angle is 90 degree

[rudraanshbhati]

Sir 10.3 is the answer, first calculate u from range formula and then put that u = v ( for the vertical motion ) and then calculate u from v²=u²-2as

[DeepakKushwaha-hdpm]

Nice sir aapka answer Correct hai aapka milte hai pure marks 😁😁😁😁😁😁😁🙃🙂😄

[suryanshsrivastava]

√106.25~10.3 mixed concept horizontal projectile and motion in 1D ❤

[teamiqavengergamer]

Mera dost jee mains m fail hone ke baad 😂

[jyotinaik]

Vertical velocity is 10 m/s. Horizontal velocity is 1.25 m/s and u is approximately 10.08 m/s.

[StrangeLucky]

Physics students trying to realx in nature... 😅

[frozanbarbiefrozanbarbie]

Jindagi ke maje lo sir 😂
Yaha bhe PHYSICS lagaoge kya !
❤

[obvhygd]

how is v=10? my method was:
2.5=vt
-5=-0.5gt^2
this gives t=1 and v=2.5
(2.5)^2=u^2 - 2gh, which gives u=10.3
can someone please help me?

[hritabratnagchowdhury]

10 m/s but i failed to galileo projectile concept becoz its not a ball

[Mandar_]

According to me the answer should be 10.3125m/s

[shreyaupadhyay]

Sir I think we have to find horizontal velocity so it will be equal to u