Prove that : sin²A cos²B - cos²A sin²B = sin²A - sin²B

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sin²A cos²B - cos²A sin²B = sin²A - sin²B
sin^2a cos^2b-cos^2a sin^2b=sin^2a-sin^2b
Prove that sin^2A cos^2B - cos^2A sin^2B = sin^2A - sin^2B
sin^2A cos^2B - cos^2A sin^2B = sin^2A - sin^2B
#math #trigonometry
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