Reverse Integer | LeetCode problem 7

Reverse Integer
Leetcode problem number 5
Solution in JAVA

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[gautamhelange]

Wow! You handled overflow condition greatly, Thank You!

[mayanksinghal]

Hello.. Thankyou for this video.
Can you explain please why can't we use overflow condition like
if (rev*10 > Integer.MAX_VALUE || rev*10 < Integer.MIN_VALUE)

[faizuddin]

Great explanation, but it would be great if you use dark theme on leetcode

[oorja]

Amazing...keep up the good work. I like the way you break down the problem on white board but please slow it down a little bit when you code.

[mathsworldbysuraj]

If number is 6804 that is containing zero and we want reverse number 4086 then what we do? according to your solution it gives 486

[sanjaykumarpandey]

Why you are dividing by 10 to check overflow condition

[KRajesh-ejdy]

Hello mam if rev>max or min we need to get output as 0 then y it is returning garbage value .Leet code is not accepting this code...

[SandraSaade]

import java.util.*;
class Main {
public static void main (String [] args){
int nums=4567;
;
}
public static int reverseInt(int n) {
int rev=0;
while(n>0){
int Lastdigit=n%10;
n=n/10;
rev=rev*10+Lastdigit;
}
return rev;
}
}