Limits Class 11 | PYQ | JEE Main | JEE Advanced |Arvind Kalia Sir| Vedantu

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Limits JEE [ Previous Year Questions 🔥] With Tricks 4 Hours Session | JEE Main & JEE Advanced 2023 | Vedantu JEE | Arvind Kalia Sir

THIS VIDEO CONTAINS:

➡️Limits JEE Main and JEE Advanced PYQS
➡️Limits JEE Main and Advance PYQS with Tricks
➡️Limits JEE Main and JEE Advance Questions
➡️Limits Previous Year Questions
➡️Limits PDFS


About Teacher 👨‍🏫: Following his passion, Arvind Kalia Sir (Mera Bhai) joined this noble profession after doing M.Sc. in Maths from IIT Delhi.

➡️ Avail all Exciting Vedantu Courses 🔥 by clicking on the links below 🤑.

➡️ Avail all Exciting Vedantu Courses 🔥 by clicking on the links below 🤑

Sounds Amazing?

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Thank you so much guys for watching the video. We hope, this session will help you get a better understanding of the topic. We would love to get your feedback. Please do comment below in the comment section.
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➡️ Avail all Exciting Vedantu Courses 🔥 by clicking on the links below 🤑.

JEEVedantu
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In due course of time vedantu jee will surpass bijyus, fiit jee & all other similar coaching classes .it is my prediction.arvind kalia is simply unbeatable.

amarendrabhowmick
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00:13:00 GINT and fractional
00:21:50 Good one, binomial knowledge
00:30:00 Good info
00:42:00 decent one
00:50:00 nice problem, i just didnt put x equals 0
00:59:00 see ok
1:04:00 Remember
1:06:00 sum

Fightclub-rm
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Sir 24:29 can be solved by taking 1+y^4 as t and then using L H'ospital Rule

sazaana
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sir lecture was soo awesome that i am waiting for you to teach other 2 hrs as mentioned on the thumbnail

CSEjn-zjed
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Behavior of this person is in another level ❤❤❤❤❤❤❤❤❤❤❤

KunalPatil
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Thank you sir for giving this trick...
Isse to question bhut easy way me solve ho gya ❤🎉🎉 28:49

k_anika
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Sir humble request to you to come up with the test series for jee mains and advance for 2022

shrniwas
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43:40❤️❤️❤️❤️❤️ my dad always tells this

harsha
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sir..that y tends to 0 wala queation where u used binomial can be simplied very easily if l hospital is aplied...4y^3 will get cancelled and job done

priyavedhanabhatla
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23:11, L Hopital is the easiest way. The problem is done and dusted in just three steps!

NiceTechAndGames
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i feel so happy, sir your teaching is amazing

ANONYMOUS-srmu
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22:00 isse bhi easy way hai
put y^4 =y because as y⁴ -> 0 , y->0
so
lim (✓(1+√(1+y))) - √2
y->0
y

now you dont have to differentiate 4 times so
apply L'hopital and that yields ans = 1/(4√2)

prashanthkumar
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u r great
im learning from ur lectures from tamilnadu....
awesome

harinikamaladharini
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Sir plz 🙏 suggest something to me when I start solving problems of hcv I solve one problem then stuck to next one and this continues and i am a jee 2023 aspirant

shreyatheinquisitivemind
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For self

7:00
13:00
17:40
26:00 ( binomial approx

atulsm
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JAI SHREE RAM SIR JI 🙏



THANK YOU SO MUCH SIR JI 🙏

thunderbird
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Awesome session sir next session straight line

ApurvaKrishnashukla
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24:28 insted take 1+y⁴=z² it will be a step solution

paravsolanki
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Sir thank you sooo much it helped me alot I'm iit JAM asprint

amaanabbasi