Boolean Algebra 3 – De Morgan’s Theorem

preview_player
Показать описание
This video follows on from the one about simplifying complex Boolean expressions using the laws of Boolean algebra. In particular this video covers De Morgan’s theorem and how it can be applied, along with the other laws, to simplify complex Boolean expressions. It includes worked examples and some exercises you can try yourself, along with solutions.
Рекомендации по теме
Комментарии
Автор

So professionally done. This is what YouTube was made for.

dickstephenson
Автор

Thank you. I am enjoying myself greatly working through these videos.

sanaalshaar
Автор

God bless this video series, it helps me to pass Computer Science class. Thanks for the info sharing, have a super day!

Szoki
Автор

I am in a 5week accelerated program for Mechatronics Engineering. Part of Mechatronics is computer science. I am in a Digital Systems 1 class. This is about as hard as it has gotten so far, and I am a junior. Drinking through a waterfall is more like it than a firehose as Iwould normally say. I am definately thankful for these videos you have made. I would be 100% lost without them. Everything is so well explained and put together and clean and concise. My text book for this course is just hard to look at in general. Thank you for these videos. I will definately be revisting them time and time again, I will not be able to master this subject in 5 weeks the way I would like, but I am already scribbling these videos into my future schedule until I can pound these expressions down with quickness and confidence. Thnak you again Computer Science! You are awesome!

jeremymcdonald
Автор

Wow, the execution of the series is just perfect

swx
Автор

Many thanks for the video, excellent resource for use with A-level CS students

katekuhl
Автор

Excellent series, what a great help it's been so far! Thanks for publishing them publicly.

joshuawaterson
Автор

This channel deserves a million subs. The videos are very to the point and helpful. I've learnt a lot from these.

mraristocrat
Автор

FINALLY some who explains each step of the solution! I couldn't find any video or tutorial about this in my first language. Each time the teacher jumped through the steps like it was all self explanatory, so eventually i started to think i was too just dumb to understand. With your videos i finally get it!! Thank you for giving me hope again ;), especially by saying it takes time to develope this skill!!

therealkon_
Автор

thank you a lot.I spend a whole day looking for a good explamention

mostafaaldgeir
Автор

At 11:48 you could remove the brackets which would result in (X V Y) ^ `X ^ Y. Using the absorptive law (X V Y) ^ Y = Y. So `X ^ Y

flandman
Автор

Thank you very much for these videos, you taught Boolean Algebra very well.

avanith
Автор

This video need more likes for his work.

RahmanullahNeazi
Автор

Thank you so much for all these videos man! Definitely valuable resources for those who didn't really pay attention during class, lol.

DrBlyat
Автор

This is very important and one must understand

yawsokpor
Автор

At 2:54 how can you just swap the OR for the AND? Wouldn't that change the meaning of the expression?

tusharmahajan
Автор

I find: ¬(A ∧ B) = ¬a ∨ ¬b
really similar to: -(a + b) = -a - b
Since both expressions switch the middle operator, and negates the values of A and B.

hugofriberg
Автор

Thank you, this series was very helpful.

shakezula
Автор

YOU ARE AWESOMEEE !!! MUCH LOVE <333

Kalahugv
Автор

Kaway-kaway sa mga gikan sa Moodle. ✋✋✋

HSAIntrovert