How To Find The Derivative of Sin^2(x), Sin(2x), Sin^2(2x), Tan3x, & Cos4x

This calculus video tutorial explains how to find the derivative of the trigonometric functions Sin^2(x), Sin(2x), Sin^2(2x), Tan3x, and Cos4x.

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[animelover-]

3:27 by using the formula 2.sin(x).cos(x) = sin(2x), we can write that ans as 2.sin(4x)

[SUBHASHKJ-pw]

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[abbiravindhran]

man thats easy! I remember on my math test, my math teacher gave cos(sin(sec(10x))) and the answer was like a fricken sentence long. Back then I hated doing so many of these trigonometric derivatives and identities, but now I wish I could go back and do them again. Just when you thought life was hard, uni comes in with integrals and series and f#$ you over. Grade 12 students, remember that practice does not always make perfect.You have to know that practise and understanding makes perfect. You can practise all day long and not understand what the hell you are even doing. Word of advise

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[RanjanKC-ukzm]

Question:
Say u change sin squared x into cos2x double angle formula for example
Cos2x =1-2sin^2x
Therefore sin^2x= 1/2 -1/2cos2x and then differentiate this

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[XC]

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[imethkariyakarawana]

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[bradayers]

Hi, great video as always however would you be able to tackle applied derivatives in chemistry and physics as well as more difficult examples

[craig]

Its so fucking confusing with the exponent written like this, only in trig the notation changes. Makes it confusing as hell with chain rule

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