Advent of Code 2023 Day 3: Gear Ratios

Very happy with my leaderboard performance today; reached #8 global!

(Disclaimer: I receive commissions on paid memberships through my link, but Codecrafters is not a sponsor of this channel, does not endorse any of my content, and does not review any of my videos.)

[YuumiGamer]

by looping around the parameter around the parameter of the digit I really struggled transitioning to part 2. I never even thought of looking at a 3 by 3 around the star.
Very insightful and I love your code!

[pietraderdetective]

your AoC videos are the best in terms of actually explaining the code's logic. All other channels usually just speed-running the codes to get the result as fast as possible, with minimal explanation in the end.

Thank you for taking the time to explain it very clearly.
You got a sub! Well done Sir!

[eavdmeer]

I started out with scanning the neighbors of the symbols as well, but missed the trick of scanning to the beginning of the number and storing only that to avoid duplicates. I then reworked to start from the numbers. Nice solution, thanks for sharing!

[MukilanKrishnakumar]

Dude, you just saved my day. I spent four hours trying to get somewhere. Finally did it because of this video. Thanks!!

[TheFrogfather]

I made a complete train wreck of part 2 up to the point where I just did a git reset and started again. Got there in the end but a horrifically messy solution that I'm definitely not sharing with anyone!

[smonratt]

I love your calm voice and explanation!

[noelomidze]

I'm just amazed by your coding skills. Amazing, man!

[zekrodev]

I was very surprised by your approach. I just simply listed all of the numbers found in the grid and then looked for the adjacent symbols afterwards. Therefore, i was able to store a list of numbers with their adjacent symbols in step two and by putting them in a hash map using the coordinate of the symbol as key I grouped them together to multiply and sum them finally.

[antonioradu]

very cool how you treated the case when you have a number all over a *
...1234....

all 3 up neghbours will go at the same start in the set and you dont get duplicate numbers

i used a list and when i got a number and gathered the digits i replaced a digit with . so when i query the next neighbour it will not see it as a number and count it twice

[marttielvisto]

You said you were discussing the problem on discord. Is it a public discord server?