CHEMICAL EQUILIBRIUM in One Shot - Full Chapter Revision | Class 11 | JEE Main

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TIMESTAMPS -
00:00 Introduction
00:40 Basics of Chemical Equilibrium
15:30 Relation btw Kp nd Kc
21:30 Significance of K
23:25 Factors affecting K
33:31 D.O.D
47:10 Le - chateliers principle
1:01:33 Relation btw D.O.D nd Density
1:01:05 Reaction Quotient
1:09:20 Simultaneous equilibrium
1:11:50 PYQs

For any queries or complaints Visit :

#chemicalequilibrium #oneshot #manzilsprint #jeewallah

[bhumeshkumarrathor]

TIMESTAMPS -
00:00 Introduction
00:40 Basics of Chemical Equilibrium
15:30 Relation btw Kp nd Kc
21:30 Significance of K
23:25 Factors affecting K
33:31 D.O.D
47:10 Le - chateliers principle
1:01:33 Relation btw D.O.D nd Density
1:01:05 Reaction Quotient
1:09:20 Simultaneous equilibrium
1:11:50 PYQs

[anshulkumar]

*Timestamps*
0:00 start to 15:30 basics

15:30 relation btw Kp nd Kc
21:30 significance of K
23:25 factors affecting K
33:31 D.O.D
47:10 Le-chatliers principle
1:01:33 relation btw D.O.D nd Density
1:01:05 Reaction Quotient
1:09:20 simultaneous eqm
1:11:50 PYQs

[asmitbisht]

TIMESTAMP(JALWA HAI HAMARA)

0:03 HELLO BACCHO BOHT BOHT NAMASKAR
0:40 TYPES OF CHEMICAL Rxn
2:56 NATURE OF CHEMICAL Eq
4:32 GRAPHICAL ANALYSIS
9:07 LAW OF MASS ACTION
14:01 DIFFERENT TYPE OF Eq CONSTANT
15:29 RELATION B/W Kp AND Kc
21:23 APPPLICATION OF K
23:30 FACTORS AFFECTING K
33:31 D.O.D
48:20 LE CHATELIER PRINCIPLE
1:01:32 RELATION B/W D.O.D AND V.D.
1:02:42 SIGNIFICANCE OF n
1:05:02 REACTION QUOTIENT
1:09:21 SIMULTANEOUS EQUILIBRIUM
1:10:47 RELATION B/W STANDARD GIBBS FREE ENERGY CHANGE AND K
1:11:57 PYQ'S
1:30:47 JINDAGI SAFAL HO GYI AAJ
1:30:52 DIL KI BAAT(THANK YOU)
1:31:30 TAB TAK KE LIYE OK BYE

PHIR MAJA AAYA PAR IS BAAR DESH KO NHI PURI DUNIYA KO DENA CHAHUNGA

[chinmoy]

TIMESTAMPS -
00:00 Introduction
00:40 Basics of Chemical Equilibrium
15:30 Relation btw Kp nd Kc
21:30 Significance of K
23:25 Factors affecting K
33:31 D.O.D
47:10 Le - chateliers principle
1:01:33 Relation btw D.O.D nd Density
1:01:05 Reaction Quotient
1:09:20 Simultaneous equilibrium
1:11:50 PYQs

thanks me later#

[wake_up_Sri_]

at 42:24 eqm conc of CO (g) =

0.8−x 0.8−0.533
= = 0.0534 mol / litre
5 5

0.533 is the number of mole dissociated
0.8−0.533 is the number of mole (left) at eqm
0.0534 is the conc of CO gas at eqm

[vasu]

1.5 hrs lecture, but all theory and concept explained very well 👌, now i can solve all pyqs 😌

[SanXb]

JEE wale channel pe NEET wale students revision krte huye 👍

[saiveeramanikanta]

This chapter was running in my class for 7 days and now by watching this video I have a satisfaction 😂😂☺️who agree 👍

[mansiumarvaishya]

00:00 Introduction
00:40 Basics of Chemical Equilibrium
15:30 Relation btw Kp nd Kc
21:30 Significance of K
23:25 Factors affecting K
33:31 D.O.D
47:10 Le - chateliers principle
1:01:33 Relation btw D.O.D nd Density
1:01:05 Reaction Quotient
1:09:20 Simultaneous equilibrium
1:11:50 PYQs

[infallible-coder]

42:50 it should be (1.6/3)/5 because they have asked for concentration so u just found the no of moles at eqm but conc is moles per litre so only 5L is given in ques

[harshthakur]

Knock Knock anyone ~ Neet 2024° 😏☺️...

[Khushi_]

Sukhriya Sir ji nd the whole (apna pyara) PW family 🙂❤️❤️❤️❤️❤️❤️❤️❤️❤️

[alwaysbehappy]

TIMESTAMPS-

00:00 .Introduction

00:40 Basics of Chemical Equilibrium

15:30 Relation btw Kp nd Kc

21:30 Significance of K

23:25 Factors affecting K

33:31 D.O.D

47:10 Le-chateliers principle

1:01:33 Relation btw D.O.D nd Density

1:01:05 Reaction Quotient

1:09:20 Simultaneous equilibrium

1:11:50 PYQS!

[gopg]

Sir biomolecules polymer environmental chemistry aur chemistry in everyday life bhi Kar na dena please please pkease

[aatharva]

sir im a aakash student and from past 3 months theres no chemistry faculty there and now we only have a month to complete 7 ch thankk uuu for support

[beabhaktgan]

Pankaj Sir's - "tab tak ke liye Ok Bye" has a different fan base 😎😎

[anbttl]

42:42 wrong. we only get x, not the concentration, to get conc. we still need to subtract it from the 0.8 we got at 41:18 to get n(at eqm) and then divide it by volume (5L) which gives us 0.05 M (approx).

[futuredoctor]

At 42:40 ans 1.6/15 hoga
hume conc nikalni hai
Aur conc moles/volume hai
Mole to x ke equal hai and x is 1.6/3
Aur volume 5L
So conc of COg is x/5
i.e 1.6/3×5
=1.6/15
May be this helped ☺️

[kirannkaur]

after watching whole lecture I was like pw is best ❤ I was trying to understand this chapter from 2 Days but this person (Respected sir) made it crystal clear in Less than 2 hrs thnq sir gbu

[aspirant]

Neet dropper watching this .. was really helpful for quick revision