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Advanced Linear Algebra, Lecture 6.3: Normal linear maps
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Advanced Linear Algebra, Lecture 6.3: Normal linear maps
Previously, we showed that commuting diagonalizable linear maps are simultaneously diagonalizable, which means that they share a common basis of eigenvectors. If these maps are self-adjoint, then they share a common orthonormal basis of eigenvectors, or in our language, a common spectral resolution. This is key to understanding precisely which linear maps have an orthonormal basis of eigenvectors, besides self-adjoint, anti-self-adjoint, orthogonal, and unitary maps. The answer are linear maps that are normal, which means they commute with their adjoints. This condition is key because if we decompose a linear map into its adjoint and self-adjoint part, as M = (M+M*)/2 + (M-M*)/2 = H + A, then M*M=MM* is precisely what is needed for H and iA to be commuting self-adjoint maps, and then we apply our previous result. We conclude this lecture by establishing several properties of normal and unitary linear maps.
Previously, we showed that commuting diagonalizable linear maps are simultaneously diagonalizable, which means that they share a common basis of eigenvectors. If these maps are self-adjoint, then they share a common orthonormal basis of eigenvectors, or in our language, a common spectral resolution. This is key to understanding precisely which linear maps have an orthonormal basis of eigenvectors, besides self-adjoint, anti-self-adjoint, orthogonal, and unitary maps. The answer are linear maps that are normal, which means they commute with their adjoints. This condition is key because if we decompose a linear map into its adjoint and self-adjoint part, as M = (M+M*)/2 + (M-M*)/2 = H + A, then M*M=MM* is precisely what is needed for H and iA to be commuting self-adjoint maps, and then we apply our previous result. We conclude this lecture by establishing several properties of normal and unitary linear maps.
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