How to Add Two Nos Without Using any arithmetic operator?????

here i am using array to pointer notation.
eg: p[1]=*(p+1);

i have taken char pointer that will increase by one

result=(int)&((&(p[x]))[y])

&(p[x])=&(*(p+x))
which is equal to p+x=0+2=2;

now remaining equation is &(x[y]) = &(*(x+y)) = x+y;

[ammarmurtaza]

apni barat ka sound to off kren video say..nonsense