Integral of sqrt(x)/sqrt(1-x^3) (substitution)

preview_player
ะŸะพะบะฐะทะฐั‚ัŒ ะพะฟะธัะฐะฝะธะต
Integral of sqrt(x)/sqrt(1-x^3) - How to integrate it step by step using the substitution method!

โœ… ๐ƒ๐ž๐ซ๐ข๐ฏ๐š๐ญ๐ข๐ฏ๐ž ๐ญ๐จ ๐œ๐ก๐ž๐œ๐ค ๐ญ๐ก๐ž ๐ฌ๐จ๐ฅ๐ฎ๐ญ๐ข๐จ๐ง

๐Ÿ‘‹ Follow @integralsforyou on Instagram for a daily integral ๐Ÿ˜‰

๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ญ๐ข๐จ๐ง ๐ฆ๐ž๐ญ๐ก๐จ๐๐ฌ ๐ฉ๐ฅ๐š๐ฒ๐ฅ๐ข๐ฌ๐ญ
โ–บ Integration by parts

โ–บ Integration by substitution

โ–บ Integration by trig substitution

โ–บ Integration by Weierstrass substitution

โ–บ Integration by partial fraction decomposition

๐…๐จ๐ฅ๐ฅ๐จ๐ฐ ๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ๐ฌ ๐…๐จ๐ซ๐˜๐จ๐ฎ

๐ƒ๐จ๐ง๐š๐ญ๐ž

#integralsforyou #integrals #integrationbysubstitution
ะ ะตะบะพะผะตะฝะดะฐั†ะธะธ ะฟะพ ั‚ะตะผะต
ะšะพะผะผะตะฝั‚ะฐั€ะธะธ
ะะฒั‚ะพั€

๐Ÿ‘‹ Follow @integralsforyou for a daily integral ๐Ÿ˜‰

๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ญ๐ข๐จ๐ง ๐ฆ๐ž๐ญ๐ก๐จ๐๐ฌ ๐ฉ๐ฅ๐š๐ฒ๐ฅ๐ข๐ฌ๐ญ
โ–บ Integration by parts

โ–บ Integration by substitution

โ–บ Integration by trig substitution

โ–บ Integration by Weierstrass substitution

โ–บ Integration by partial fraction decomposition


๐…๐จ๐ฅ๐ฅ๐จ๐ฐ ๐ˆ๐ง๐ญ๐ž๐ ๐ซ๐š๐ฅ๐ฌ ๐…๐จ๐ซ๐˜๐จ๐ฎ
โ–ถ๏ธ Youtube

๐Ÿ“ธ Instagram

๐Ÿ‘ Facebook

๐ƒ๐จ๐ง๐š๐ญ๐ž
๐Ÿ™‹โ€โ™‚๏ธ Patreon

IntegralsForYou
ะะฒั‚ะพั€

A shortcut: sqrt(x)*dx = (2/3)*d(xsqrt(x)) and x^3 = (xsqrt(x))^2 so the integral becomes:
int of which is (2/3)*arcsin(xsqrt(x)) + C.

ernestschoenmakers
ะะฒั‚ะพั€

substitute x^3=sin^2(t), dx/dt=2cos(t)/3(sin(t))^1/3 ... works well

gsg
ะะฒั‚ะพั€

merci pour cette intรฉgrale, excellent double changement de variable,

syphaxjuba
ะะฒั‚ะพั€

Please periodically move your hand out of the way once you've written something down. For the majority of this video, the calculation can't be seen. It makes the process very hard to follow.

gentlemandude
ะะฒั‚ะพั€

Your handwriting is absolutely wonderful!

monikaherath
ะะฒั‚ะพั€

substitute t = sqrt(1-x^3)

(-2/3) dt/x^2 = dx/sqrt(1-x^3)

sub back into integral
-2/3 integral x^(-3/2) dt

by manipulation, x^(-3/2) = 1/sqrt(1-t^2)

hence
(-2/3) integral [ 1/sqrt(1-t^2) ] dt

just apply rule on integral to obtain
-2/3 sin-1(t) + C

slightly longer but easier for me

_jayjay
ะะฒั‚ะพั€

I am a new subscriber, in love with your channel.. where have you been all my life
Thank you so much ๐Ÿ™

sleepystuff
ะะฒั‚ะพั€

pls solve a qstn for me
integral of (1-x^2)sinxcos^2x from pi to -pi

jaspalverma
ะะฒั‚ะพั€

Podrรญas ayudarme por favor :)

Integral of dx/(x^2 sqrt(9 - x^2))
integrate 3x + 1 dx/x^2 + 4x + 3
integrate x dx/ x (x + 2)^2
integrate dx/ x^2 sqrt(4 + x^2)

diegoguerrero
ะะฒั‚ะพั€

Hola podrias ayudarme con esta integral?
Integral de dx/(x-3)sqrt(x^2-6x+5)

luisgianpierocastanedabarr
ะะฒั‚ะพั€

Please solve โˆšx^2+1รทx^4 integration i.e. integration of under root x square +1 divided by x raised to 4

satishdhage
ะะฒั‚ะพั€

Una pregunta: ยฟpor quรฉ no se eliminan como primer paso ambas raรญces de tanto numerador como denominador? ยฟNo simplificarรญa mucho mรกs todo el proceso? En cualquier caso, gracias por el video, te has ganado un colacao!

darksaske
ะะฒั‚ะพั€

Can we take root(1-x^3) as u and solve??

YOYO-zyyj
ะะฒั‚ะพั€

Do me a favor. Please Integrate xarctanx/(1+xยฒ)^(3/2) .
This has made me mad. No website has step by step solution for this๐Ÿ˜ญ๐Ÿ˜ญ

chandrakumar
ะะฒั‚ะพั€

do you get money from your videos ? asking coz i appreciate your work

gorangjangid
ะะฒั‚ะพั€

Hi! Can you integrate (x^7/2)/sqrt(1-x^3). I can't find it anywhere :/

iguess
ะะฒั‚ะพั€

U =โˆšx ->x^2=x->x^6=x^3 I can't understand please explain this..

culturalandeducational
ะะฒั‚ะพั€

Hii.. I want the answer for integration of e^โˆšx cose^โˆšx/โˆšx . Say the ans sir...

upender
ะะฒั‚ะพั€

I did u=x^(3/2) but I can't get the u^2 at the denominator to reach that arcsen formula. Google shows this way to solve it, but I don't know how to reach that f*** u^2. Hopefully you can see this and explain it to me. Also, I rewrote sqrts as exponents, you know, โˆšx=x^(1/2)

NicolasSpiaggi