Golang Tutorial #14 - Range & Slice/Array Examples

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This golang tutorial covers the range keyword and illsurates some common proramming problems and solutions that deal with arrays and slices.

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⭐ Tags ⭐
- Tech With Tim
- Golang Tutorial
- Go Range
- Arrays & Slices Golang
- Golang slices
- Go Arrays

⭐ Hashtags ⭐
#GO # Golang

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Комментарии

Thanks bro, your lessons best, cause:
1. Just the most important inf.
2. Professional lector
3. Easy understanding spelling.

So, thank you for your spended time!

nb-cycw

That was a good approach, using the > operator to detect duplicates within the same slice. It's way more efficient than storing the duplicates.

msolomonbush

Thank u Tim, your explanation is great that someone new to programming like me can understand with ease. Appreciate man

anhtu

Hey thanks for making the code font size WAY bigger than default, for our benefit. Few do this.

thisisreallyme

adding break after you print will increase performance and only show the duplicates. great video!

TonoNamnum

this is good. slightly challenging for beginners to think and grow their skills with the basic syntax.

good teaching about the ways to deal with simple challenges using array/slice index, for loops, length, empty return, a more effective solution than to redo the same comparison on the same index.

bennylee

you can also acheive this by taking a slice of your slice:

for i, element := range a {
for _, element2 := range a[i+1:] {
if element == element2 {
fmt.Println(element)
}
}
}

jamisonwilliams

That's great Tim I code with python now I saw this video I really want to learn GOLANG

tunisiancommunityforcoders

this is my solution :)
var list = []int{1, 2, 3, 4, 5, 2, 4, 5}

for index, element := range list {
for _, subElement := range list[index+1:] {
if element == subElement {
fmt.Println(element)
}
}
}

محمدباقرملایی

After this series, Can we have some cool projects built in Golang?

dheerajlalwani

This will also work:
func main() {
mySlice := []int{1, 2, 3, 4, 5, 4, 6, 7, 8, 4, 9, 6, 9}
duplicates := make([]int, 0, len(mySlice))

fmt.Printf("The duplicates are: ")
for i, x1 := range mySlice {
for _, x2 := range mySlice[i + 1:] {
if x1 == x2 {
duplicates = append(duplicates, x2)
}
}
}
fmt.Println(duplicates)
}
but not for more than one duplicate, though, e.g. a third (fourth...) 6 or 4, in this example. As some people pointed out, Tim's algorithm also runs into this problem. Here I just wanted to show the use of element2 := range givenSlice[i + 1:] - making a slice of a slice that begins with the element that's one after the ith.

nenadilic

Hey 15:03 if u inject 3 same digit it will print wtf is it

Thelostblud

Is this another great video? ✌ always the best content✌ keep it going bro

michabilski

Why not just use slice in the second for like this? It would work the same way. (not trying to sound bitchy, just thought about this)
for i, element := range a {
for _, element2 := range a[i+1:] {
if (element == element2) {
fmt.Println(element)
}
}
}

Great job either way, thanks man!

KillFStudio

Try using this array/slice. {1, 3, 4, 56, 7, 112, 4, 9, 4, 99}. All thread 4's are being printed out. I think in this case we wanted only two 4's printed out. I could be wrong???

csharpusa