LeetCode 55: Jump Game | Java Solution | Greedy Approach

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📊 In this video, I solve the #jumpgame problem on LeetCode, where we need to determine if we can reach the last index of an array by jumping forward. #dynamicprogramming #greedy #leetcode #javacoding

⏱️ **Time Complexity**: O(n) where n is the length of the input array
🧠 **Space Complexity**: O(1) constant extra space

## 📝 Timestamps
00:00 - Understanding problem statement
01:04 - Brute Force approach
02:17 - Improving with Dynamic programming
03:29 - Optimal solution - greedy algorithm
05:48 - Big O Notation explained
06:16 - Java code walk-through
06:56 - Solution analysis - runtime + memory
07:04 - Conclusion

## 🔑 Key Concepts
- Greedy algorithm
- Array traversal
- Optimal decision making
- Reachability problems

## 📚 Learning Points
- Understanding when to apply greedy algorithms
- Working backward for optimization
- Converting complex problems into simpler subproblems
- Handling array boundary conditions efficiently

## 🔄 Related Problems
- LeetCode 45: Jump Game II
- LeetCode 1306: Jump Game III
- LeetCode 1345: Jump Game IV
- LeetCode 1696: Jump Game VI

## 👥 Target Audience
This video is for intermediate programmers preparing for coding interviews with companies like Google, Amazon, and Microsoft, as well as computer science students looking to improve their algorithm skills.

## 📋 Prerequisites
- Basic Java syntax knowledge
- Understanding of arrays
- Familiarity with time and space complexity analysis

## 🔗 Links

## 💡 Additional Tips
- Pay special attention to the greedy approach's direction (working from end to beginning)
- Remember that we only need to determine if reaching the end is possible, not the minimum number of jumps
- Practice identifying when a problem can be solved greedily versus requiring dynamic programming

If you found this solution helpful, please like and subscribe! 👍 Drop your questions or alternative approaches in the comments below. I respond to every comment! #codinginterview #algorithmsanddata #softwareengineering
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💻 Full Solution Code Available!
You can find the complete implementation for this problem here:

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