Return a Sorted Array Without Changing the Original Array - Functional Programming - Free Code Camp

[paulfanning]

Trying to get a job in web design and ur helping so much really appreciated

[zken]

The answer has been changed and or updated Mr. Ian to this
const globalArray = [5, 6, 3, 2, 9];
function nonMutatingSort(arr) {
return [].concat(arr).sort((a, b) => a - b);
}

[gorank]

But this would not work if you had for example 10 in that array,
then 10 would be first number in new array because numbers are converted to strings.
You should do it with callback function. Here is mine solution:

const globalArray = [5, 6, 3, 2, 9];


function nonMutatingSort(arr) {
// Only change code below this line
let newArray = [...arr];

function compareFunction (a, b){
return a-b;
};
return

// Only change code above this line
}

nonMutatingSort(globalArray);

[zacharyfranczak]

another option

const globalArray = [5, 6, 3, 2, 9];

function nonMutatingSort(arr) {
// Only change code below this line
return [].concat(arr).sort(function(a, b) {
return a - b;
});

// Only change code above this line
}

nonMutatingSort(globalArray);

[kita]

this method doesnt pass the test. Thanks