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[davidseed]

multiply ab=15 by bc=30 gives
abbc=15*30
divide by ca=15*3
b²=10, b=√10
subs b into ab=15 gives a=1.5√10
subs b into bc=30, gives c=3√10
a+b+c=(1.5+1+3)√10
a+b+c= 5.5√10 or 11√10/2

[seancrowe]

There are two sets of solutions. Any time you take the square root of both sides, there are positive and negative solutions. The values a = -3/2*sqrt(10), b = -sqrt(10), c = -3*sqrt(10) is also a solution. This gives a + b + c = -11/2*sqrt(10) as another solution to the overall problem. I hope the examination markers were more astute than the person who presented this video! 😊

[mohamadpakzamir]

abxbc+abxac+bcxac=2475=
25x9x11

abc(a+b+c)=25x9x11. (1


1/ab+1/ac+1/bc=(a+b+c)/abc. (2
1/15+1/30+1/45=1/90(6+3+2)=
11/90
(1), (2)

(a+b+c)^2=(25x9x11)x11/90

a+b+c =(5x3x11)/√90
=(5x3x11)/3√1o
==(55√10)/10 =(11/2)√10

[RealQinnMalloryu]

3^5 (ab ➖ 5ab+3). 2^15 2^3^5 2^3^5^1 2^3^1^1 2^3 (bc ➖ 3bc+2). 3^15 3^3^5 1^3^5^1 1^3^1^1 3^1 (ca ➖ 3ca+1).

[ichdu]

this is acoustically really hard to understand. Problmes with the microphone???

if ab = 15, then b = 15/a
in bc =30 you replace b and receive c = 2a,
in ca =45, replace c and receive 2a² = 45 ---> a = +/- 3/2 root(10) --> c = +/- 3root(10)
--> b = +/- root(10)
finally a+b+c =+/- 11/2root(10)

[СергейБоборев-съ]

С этого ясно что 15/в=45/с. 15/а=30/с. Тогда 45/а=90/с И и 45/а=30/в. . Тогда 90/с=30/в и ТД. Долго решать таким методом.