Circuit Power Dissipated & Supplied Analysis Practice Problem (Electrical Engineering Basics Review)

Remember, P = IV = (I^2)(R).

Passive Components, and Semiconductor Basics.

---WANT MORE EE VIDEOS?---

---FAVORITE EE REVIEW BOOKS---

---MORE COLLEGE COURSE VIDEOS---

[randombuilder]

Hey, Just wanted to thank you, years ago i had seen your videos a night before my basic electrical engineering exam, your videos helped me clear the exam somehow. Thanks.

[Nitodvd]

You explained this in a simple way and helped me understand since my professor sucks at explaining 🙏

[Vnifit]

Fantastic! Just what I was looking for, super clear explanation!

[gamerkinga.c]

Thankyou so much sir, just exactly what I was looking for

[phuephue]

Thank you so much for such a great video!!!!

[Zonneschijno]

I got the last one by adding al the previous calculated data together and adding what would make zero. Seems like it works and it's a lot easier. xD

[janamishaal]

When finding p4, why did we use i=5A ?

[sijiayong]

how I know that where should I assign positive n negative for that dependent currenct source?

[saimahcosain]

How about the power delivered by the voltage source ?

[learneeartist]

Sir why didn't you take the sign convention for when voltage is taken into picture

[ultralaggerREV]

What if the voltages in those resistors were replaces with ohms and the current dependent current source was replaced by a voltage dependent voltage source?

And also that 6 A is unknown

[mokarrommolla]

hey man, I have an question for you. why did not we use 20 v for p4 instant of not using 8 v?

[adonis]

Fuck yes. Thanks for the awesome swift explanation

[yanjarappak]

Sources supply power, whereas resistors obsorb that power

[sanzharserik]

I can't understand why current (-0.2 A) ?

[quinstermyer]

i thought if the current went out the positive battery it would be positive? why is it negative?

[StoneShards]

How does a resistive circuit element consume power? Everything I've seen says electric current moves extremely slowly, like a millimeter per hour. So, it's going to take many hours for a specific electron to get from one end of the RESISTOR to the other! This "drift velocity" seems more or less constant. I always assumed current flow occurred at a high enough speed that its speed wouldn't be any kind of issue. I see a simple circuit diagram and try to realize that the electrons that make up the current flow will take centuries to move around the circuit ONE TIME! Then, too, what is a "current waveform"?

[thomasv]

i thought voltage in a parallel stayed the same.

[miguel]

isn't the power across a resistor found with I^2 x R ??

[LearnDeutschwithzozo]

Your explanation is not clear, u should explain its details too, u r just calculating and saying it should be calculate like this u didn’t say anything about how and why it should be calculated like that. 👎🏻