Electrical Engineering: Ch 11 AC Circuit Analysis (8 of 55) Thevenin Theorem Example

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In this video I will show the 5th, Thevenin theorem, of the 6 methods where the current, I2=?, the portion of the load impedance is remove and short the voltage source and leave open the voltage source.

Next video in this series can be seen at:

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You helped so much in my college life professor. Thank you so much.

jarubyjane

Dear professor,
All what you upload are very clarifying and helpful. I appreciate your chanel. Please continue uploading more.
Daniel S.A.

danielsolomonaraya

this is great work .. i thank you mister

jugurthagreen

Sir how did u know that V=va-vb
Can it be V=vb-va?

muhammadyunus

SIR, in the end at the thevenin equivalent I applied KVL at that loop I get the same result but in minus (_j8+j4_3) and current will be (_9, 90/50, 84), in DC circuit we used to care about the sign since the current flows from higher electric potential to lower electric potential, please correct me if I am getting wrong, also, do we put the sign for the component impedance or just for one single element

wegdanfarea

Sir, I didn't get why did you add minus sign in front of 49.51 at 5:34

gulergedirli

Sir greetings here from the Philippines! I just wanna ask how will i find Zth (in thevenin) or Zn (in norton) if a resistor of, let's say 6 ohms would be placed in parallel to the j8 inductor?

aiura

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