Thermodynamics 1-71 Consider a U-tube whose arms are open to the atmosphere. Now water is

Thermodynamics 1-71

Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (ρ = 790 kg/m3) from the other. One arm contains 70-cm-high water, while the other arm contains both fluids with an oil-to-water height ratio of 4. Determine the height of each fluid in that arm.

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[SuemonKwok]

Alternative way to solve it using pressure balance method. The python code below

# Given values
rho_w = 1000 # Density of water in kg/m^3
rho_a = 790 # Density of oil in kg/m^3
h_w1 = 0.7 # Height of water in one arm in meters
ratio = 4 # Oil-to-water height ratio

# Calculate the height of water in the arm with both fluids
h_w2 = h_w1 / (1 + (rho_a / rho_w) * ratio)

# Calculate the height of the oil column
h_a = ratio * h_w2

# Print the results
print(f"Height of water in the arm with both fluids: {h_w2:.3f} meters")
print(f"Height of oil in the arm with both fluids: {h_a:.3f} meters")

[BafinuBareng]

Cannot understand your expectations here🤔