Optics: Plane Mirror. Level 3, Example 1

Optics: Plane Mirror. Level 3, Example 1

A light bulb is a distance d1 = 2.50 m above the surface of a swimming pool filled with water to a depth of d2 = 2.00 m, as in the figure. If the bottom of the pool is a plane mirror, how far below the mirror is the blub’s image?

[valeriereid]

Thank you so much for explaining this thoroughly and for not missing any of the steps. This certainly helps.

[vinugi]

Thank you sir! you're an absolute life saver, I've been trying to solve this for 45 minutes and you did it in 5 minutes

[amanraj-ssxh]

He solved the question like it was a child's play for him and I have been trying to solve it for over half an hour (from my high school textbook)....😥

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[GavinLi-ietl]

Thank you so much for getting me unstuck with my assignment -- subscribed!!

[instant_mint]

This helped me understand, thank you!

[michaelhammer]

This may be silly, but shouldn't the light just go straight down and then bounce straight back up. of we just make theta zero then shouldn't it just be d1 + d2. obviously, this is not correct, but It seems to work out mathematically. if the mirror was at the surface of the water it would just be d1 right?

[alex_turing]

Shouldn't the bottom of the pool appear higher than it actually is?

[jediclone]

Why do we use the refracted ray that came out of the water? Shouldn't it be the reflected ray off the mirror?

[pushkarpriyachand]

Sir how do we know that the image Is formed directly below the object?