Integral of (sinx cos2x) ❖ Calculus 1 ❖ Trig Integrals

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This video works through the integral of (sinx cos2x). This type of integral is typically found in a Calculus 1 class.

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I substituted sin²x instead of the cos²x, travelled all across the globe and still manage to reach the answer. The real journey was the friends we made all along the way.😂

lenops-uubw
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thanks for the straight forward explanation. helped me a lot in my studying

nostalgiacademy
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Great video. Thank you! Very straight forward and simple way to explain it!!

willdavila
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Greatly appreciated. Thanks for making math videos.

dougjenkins
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thank you so much! It's really an easy way to understand!

chitranlinh
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Too many steps cause int of sin(x)*(2*cos^2(x)-1)*dx doesn't have to be expanded.
Apply a u-sub:
Let u=cos(x)
du=-sin(x)*dx, plug this in:
I = int of sin(x)*(2*u^2-1)*du/-sin(x), both sines cancel so you'll get:
I = int of -(2*u^2-1)*du
I = int of (1-2*u^2)*du = u - (1/3)*u^3 = cos(x) - (1/3)*cos^3(x) + C.

ernestschoenmakers
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I always have this question, when you do the u-sub for cos^2x, where does the square go?!! we just treat it as it is raised to the the1st power?

Thank you,

xOxAdnanxOx
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Nice video! Thanks for your explanation!

kailee-cyms
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Thanks Cole. I don't care what they say about you on the schoolyard, you're alright.

rilesbeme
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can we use
sinx cos2x =1/2 ((sinx-y)+sin(x+y)) formula

Devastator_
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