LeetCode Medium 176 Amazon Interview SQL Question with Detailed Explanation

In this video I solve and explain a medium difficulty leetcode SQL question using MySQL query. This question has been asked in Apple, Facebook, Amazon, Google, Adobe, Microsoft, Adobe interviews or what we popularly call FAANG interviews.
I explain the related concept as well. This question includes points to keep in mind to develop SQL queries.

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[rushikeshjaisur]

We can use MAX(salary) to handle null .
with RankTable as
(select *, dense_rank() over(order by salary desc) as rnk from employee)

select MAX(salary) as SecondHighestSalary from RankTable where rnk = 2;

[meenayegan]

Alternate 1: case-when

select case when dr = 2
then salary
else null
end
as secondHighestSalary
from
(
select *,
DENSE_RANK() over (order by salary desc) dr
from employee
)x

Alternate 2: coalesce

select coalesce
((
select salary
from
(
select *,
DENSE_RANK() over (order by salary desc) dr
from employee
)x where dr=2
), null) as secondHighestSalary

[mohammedjunaidazhar]

SELECT MAX(salary) AS SecondHighestSalary
FROM Employee
WHERE salary < (SELECT MAX(salary) FROM Employee)

This query is working too.

[chiragshetty]

can anyone hellp me with solution for mssql, i'm trying with offset but not getting the solution

[ujjwalvarshney]

select max(case when x.ct >2 and x.rk=2 then salary when x.ct<2 then null end ) as SecondHighestSalary from
(
select *, Count(*) over() as ct, rank()over(order by salary desc) as rk
from Employee) as x