Find the points on the x axis which is equidistant from (2,-5) and (-2,9)

Find the points on the x axis which is equidistant from (2,-5) and (-2,9)
Solution:let point=(x,0)
Distance of (x,0) from (2,-5)=√29-4x+x²
Distance of ( x,0) from (-2,9)=√85+4x +x²
ATQ √29-4x+x²=√85+4x +x²
-8x=56
X=-7
(-7,0) isanswee#MathHelpers#Findthepointsonthexaxiswhichisequidistant from (2,-5) and (-2,9)

[ubaidahmadubaidahmad]

good trick I will understand all method thanks

[manjular]

Ma'am it was very helpful and I understood the question well

[ayushmankashyap]

At starting no feel that when she was making video any earthquake had come...🤣🤣🤣🤣🤣

[jadhavlaxmi]

Really helpful mam saw many videos but couldn't understand among all the videos this is the best one

[abdulazeem]

What formula are you using of (a-b)2 in third line of the problem

[kalashsharma]

Thanks mam u explained very well I have seen a lot of videos but I couldn't understand but after this video I had understand this question thanks for teaching

[KR-DOLLARSIGN]

Mam kya ek hath mein camera ley kar dusray hath se likh rahe ho kya....itna hila kyun rahe ho...

[kfmmm]

Can't we apply here middle point theorem here ???? Plz tell

[saintdurden]

Mam u have taken minus common...and didnt used it how it can be correct..
Someone please explain me🤔😫😥