Class 9th Maths Circles | Most Important Questions

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Ans :

In ∆AOB,
Since OA = OB = radius
<BAO = <ABO = 30°
[as angle opposite to equal sides]
Similarly, <OBC = 40°

So, <ABC = 70°
Therefore, <AOC = 2 X <ABC
= 2 X 70°
= 140°

So, x = 140°

educational_line
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140 using angle sum property of triangle and angle around a point

krrangarajan
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In ∆ABC,
Angle BAO + Angle BCO = 2×angle AOC
Then,
30°+40°=70°
2×70°= 140°
Angle AOC = 140°

priyammallik
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solutions -
OA = OB (RADIUS )
angle - OAB= ABO
OB = OC (RADIUS )
ANGLE - ABC = ABO +OBC
ABC= 30 +40
ABC = 70
REFLEX AOC = 2ABC
REFLEX OF AOC = 2 X 70
REFLEX OF AOC = 140

crazyboyz
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angle ABC is 110°. Angle of arc subtented at the centre twice the angle subtended at any point of circle. if angle ABC =110 then angle AOC=220.

psvprasad
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110 ans hai angle sum property 30plus 40 is 180 subtract

AdarshPatel-ho
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The real answer is 220° using theorem:9.7."Angle on centre is double of any angle made at any point at circle"😊

UltronZgaming-qori
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140 ans. Because r ao & r bo is equal then LB is 30 and same other triangle

Jentle_Shukla
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140 angle subtended by an arc at cente is double of angle subtended by remaining part

SīīləŋtKīīlər
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Sum upper 2angles andMultiple with 2 we can know the lower angle . Hence it is140

PushpaKumari-qvvn
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55 is correct answer for this question

unknowngirl_salu
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180-40=140
140-30=110
X=110
Hence proved

Daksha_DP
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30+40+x=180
70+x=180
X=180-70
x=110 ❤❤is write answer

RekhaVerma-kw
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Angle ABO =30 degree
Angle OBC= 40 degree
Both sum =70 degree
Angle AOC= 2 X angle ABC
=2 x 70
= 140 degree


Hope this helps

khyatiprabha