Python program to check if a year is leap year or not

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Music Credits:
Music: Achaidh Cheide
Musician: Kevin MacLeod

Program Code:
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year=int(input('enter the year:'))
if (year%4)==0:
if (year%100)==0:
if (year%400)==0:
print(year,'is a leap year')
else:
print(year,'is not a leap year')
else:
print(year,'is a leap year')
else:
print(year,'is not a leap year')


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[maxssinec]

2100 is leap

it's better to do this:
enter = int(input("enter year: "))

if enter%4 == 0:
print(enter, "leap year")

else:
print(enter, "not leap year")