Multivariable Calculus | Triple integral with spherical coordinates: Example.

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We present an example of calculating a triple integral using spherical coordinates.

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Every time I see some beautiful multivariable calculus like this I am in awe. These techniques really allow us to do hard stuff so easily...

tomatrix
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I’m grateful for watching this video with such a lucid explanation. God Bless you sir

unclesam
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Pretty sure the answer is more complicated than that...
The first integral evaluates to (4^5)/5 = 1024/5, not 2048/5
the second integral is fine
The third integral evaluates to (1-sqrt(3)/2), not 1/2, as cos(pi/6) = sqrt(3)/2, not 1/2
The answer is 512pi/5*(1-sqrt(3)/2)

Making mistakes on the blackboard is fine as long as they are corrected. However, I am shocked that there are no amendments to this video 2 years after it has been released. This shouldn't happen and I hope Penn can correct this so students would not be confused.

rebucato
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I hope you are doing well and everything in your life is going great! Thank you for this! Wow!

betramlalusha
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I think it is necessary to check whether the top sphere actually touches the bottom cone, cause if i change the limits for y to from 0 to sqrt(1-y^2), then the answer would be very different and also 0<x<1.

Martin-iwll
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Michael Penn has awesome teaching skills

noahifiv
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You explain this problem very smoothly

userHamza
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Thanks for the video! For some reason I had more success understanding you than my professor.

seanfischler
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Hi. I am interested in how one can determine boundaries of integration when there is no a explicit function for z in terms of y, or y in terms of x. For instance, calculate the volume of body bounded by following surfaces: x^2+y^2 = cz, x^4+y^4=a^2(x^2+y^2) and z=0.

dalibormaksimovic
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but how can the radius be 4 if y is bounded by [0, 2]

maxyao
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Consider the hot air balloon with equation 9x^2 +9y^2 +4z^2 = 100.
The temperature in the hot air balloon is given by the following function: f(x, y, z) = 18x^2 + 18y^2 + 8z^2 − 20

• Convert the regular area into appropriate spherical coordinates.
• Calculate the volume of the balloon.
• Calculate the average temperature in the Balloon

Carusot
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Maybe somebody can help me out: I know you can see the bounds for theta on the board, but is there an algebraic way to derive them from the equations and the xyz bounds ?

walter
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how to determine exactly what’s the equation is????

sarykhalaf
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Coolest way to end the video saying" Good now it's a good place to stop"😂😂

jaineshmachhi
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Excelant i realy enjoyed god bless you

majidrazavi
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In this problem becomes x^2+y^2=4, which means that the intersection of the cone and sphere are at the same as the limits on the x-y plane, but if the bounds on x had been 0, sqrt(1-y^2), then you would've had a spherical section on top of a cylinder on top of a cone. I'm not 100% sure how I would convert the equation if that was the case. It may require changing it to two separate integrals, one where phi goes from 0 to csc^-1(4) and rho goes from 0 to 4, and a second where phi goes from csc^-1(4) to pi/6 and rho goes from 0 to csc(phi).

ThAlEdison
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4^5 is not 2048 and and cos(pi/6) is not 1/2

unconscious