Java Tutorial: Variables and Data Types in Java Programming

Java Tutorial (Variables and Data Types): This Java tutorial for beginners will teach you about primitive and non primitive data types in java programming from scratch. This complete java course will help you master all the concepts you need to learn in Java.

Best Hindi Videos For Learning Programming:

►C Language Complete Course In Hindi -

►JavaScript Complete Course In Hindi -

►Django Complete Course In Hindi -

Follow Me On Social Media

[CodeWithHarry]

I am doing my best to create the best Java Course for you. Please do your part by sharing this video!
Instagram: Instagram.com/CodeWithHarry

[muskansingh]

I've never commented before on a YT video but code with harry deserves it. So much efforts and mad hardwork, last time I saw this video 2 years back when I was doing my btech, now watching it again when I'm switching job. 💯 hats off!!

[abheygupta]

He is literally putting his most efforts. He deserves billions.

[dishasinghania]

The way you have explained basics is beyond excellent. I find myself lucky to have come across your course.

[rishabkumar]

THIS PERSON IS MORE IMPORTANT THAN ELON MUSK.

[abufarhaz]

Bro Harry, why did I not see your videos before! I have been struggling to learn Programming for so long. You just made it easy. Thank you so much. Because of your good and hard work people like us get hope. I will always be grateful to you.

[RealAdiBhaiya]

18:14 - The generic form for the range will be from - ( (2^(N*8)) / 2 ) to + ( ( (2^(N*8)) / 2 ) - 1 )

[anujchaudhary]

sir you are the best teacher i have ever seen. i learned html, css, javascript, php, C programing and now i on the way to java and i think this will continue in future also. Thanks a lot sir😇❣

[asmitagumber]

Range of a data type that takes 'n' bytes of space would be : - (2^ n*8)/2 to +[(2^ n*8)/2] -1
total space it occupies : n bytes
total bits it can hold : n*8 bits
total values would be : 2^ (n*8)
so, range would be : [-2^ (n*8)]/2 to [+2^ (n*8)]/2 -1

[ayandutta]

If n bytes. Then 1st n*8=8n
Range is :
-{(2^8n)/2} to [{(2^8n)/2}-1]

[vikaskaushik]

Nice video sir, you are the best teacher in my whole life 😍😍😍😍😍

[srinukannedi]

Never commented on YouTube but Harry deserves it
Such a great work 👏
Amazing course

[KajalSingh-xgjp]

For n bytes, range will be from ((2^(8n))/2) to ((2 ^(8n))/2) - 1

[abhinavshesware]

I started learning Java. But there were a lot of courses and books that were available. But you did a fantastic Job of making it simple and providing relevant notes that too free of cost. Hope you have a wonderful career and this channel gets acknowledge for being as fantastic as it already is.

[knowatease]

I was thinking to take computer classes but after watching your videos I changed my thoughts. I don't know anything about computer but the way you are teaching is commendable. It is easy to understand.
I want to ask a question that "is this playlist contain complete java's topic? "

[aarushsanga]

00:02 Java course covers Variable and Data Type
03:29 The anatomy of a Java program
06:37 Variables and Data Types in Java
09:43 Variable Naming Rules in Java
12:49 Java has eight primitive data types
15:54 Different Data Types in Java
18:34 Java Primitive Data Types
21:24 Java program to add three numbers
Crafted by Merlin AI.

[abhiaryan]

18:20 The formula for calculating the value range of a data type of n bytes is :-
Let n'=n*8
-2^(n'-1) to 2^(n'-1)-1

[KoushikDas]

June 14 2023
Completed it.
Will be there again tomorrow for revision.
Consistency is the challenge ❤

[masst]

Yes is a real coder, teacher, helper, and a god gift. Pls pls pls share his playlists

[singh]

System.out.println("amazing java course");
System.out.println("best teacher on youtube");