#35 JavaScript Bangla Tutorial | for loop

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In this Part 35 video of JavaScript Bangla Tutorial Series for Beginners, I have explained about JavaScript for loop.

References:

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#javascript #js
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vai apner amon udar manushikota sotti amader k obak kore. apni bangladesh er programming er jonno ja kortesen sotti oshadaron. apner hat dhorei amra onek beginner programming er jatra suru koresi.apni asholei amader jonno akta GOD gifted person. nijer jotno nean dhonnobad

sizanahmed
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এত সুন্দর এবং সহজ সাবলীল ভাষায় বুঝিয়েছেন যে, না বোঝার কোন উপায় নেই। ধন্যবাদ

AbdulJabbar-vfdc
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Alhamdulillah, what an amazing teacher you are. I am an old guy but novice in computer and got encouraged so much from your teaching .May Allah give u the most content life in this world and in the hereafter. Bangladesh needs more guy like you.

aminulislam-ibbo
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Completed the JS for loop video. Understanding the loop and loop scope.
LWSB ❤️

webdevsumon
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Thanks for the detailed video Dada. Very informative💖 Watch Date: 23-12-2023

MarufHasanShihab
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excellent tutorial... Thanks, vai ❤❤💚💚

mdrakibhossen
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আমি যদি w3school অনুযায়ী language by language পুরা টা শিখি তবে কি basic and advance হয়ে যাবে(সংশ্লিষ্ট language)।

khairulalam
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I don't know how to praise people like you, sir.

anunayargha
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দাদার ভিডিও তে শুধু "ডলার" এর এড আসে 😁😜

arifulhaqchowdhury
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one-time video watched, one-time documentation read, and lastly give the quiz. is it enough for the best practice?

programming-dude
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Loop concept is very confusing in every language not much hard but its confused me a lot 😴😴😴😴

xyz--
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Sumit vai, text = text + cars[i];
Ata bujhtai parcena. Aktu help koren na vai please.

palash
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// Solved 2 problems after the loop tutorial.
// Problem 1 Start
const bestFriends = ['Rahim', 'Karim', 'Jamal', 'Kuddus', 'Abbas'];
let arrayLengthMegerment = bestFriends.length;
for (let i = 0; i < arrayLengthMegerment; i++){
console.log('My best friend is' + ' ' +':' + ' ' + bestFriends[i]);
}
// Problem 1 End

// Problem 2 Start
const oddNumbers = [];
let totalCountNumbers = 10
for (let i = 0; i <= totalCountNumbers; i++){
if (i % 2 == 1){
oddNumbers.push(i);
}
}
console.log(oddNumbers)
// Problem 2 End

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