Solve a word problem using vectors, airplane and wind

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Timestamps:
0:00 Intro
0:20 Start of Problem

Corrections:
3:18 It's not 50 degrees but 50mph.
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I wish that there's more teachers in the world like you to help students like us.

shiqizhou
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Thank you. I was really struggling with this concept but you explained it very well !

renan
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When pilots are given wind direction and speed the direction is where the winds coming from, so if wind is given as N45degE at 50 mph the wind is blowing from N45degE so it should be shown in the opposite direction in the example. Yes??

coolbombe
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I understand the concept you are trying to explain, but what are we referencing speed and direction to? If we are using the ground as a reference, then the answer is his direction is 17 deg, and speed is 340 mph. If we are using air speed and his aircraft’s compass as a reference, then it is a different calculation than the one presented.

Thank you, I do enjoy your bearing discussions.

duncansmith
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As a math teacher I gotta say its nice to see others making the same little mistakes as me; its almost as if teaching and doing math use different brain processes

MathGPT
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Personally. I find using the Sin rule by itself and then cosine rule by itself is quicker.

muhammadshuhelamin
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I really should’ve taken pre calculus before physics with algebra one. This make more sense. It’s a good thing I’m taking pre calculus next semester. Got plenty of resources for the class :)

christie
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OK WAIT THIS IS LITERALLY THE PROBLEM I NEEDED HELP WITH

avazquez
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why are you adding a and c and not and a and b isnt a and b together?

aryangandhi
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Great video, thank you very much. My only problem is the use of the storing answers to from the calculator.

terencewright
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how did he use the tangent if it isnt 90 degree

Mr
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hi, if you add the wind vector's tip(?) to the plane vector do you get the same result?

jess
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How did you get 50 degree on resultant vector?

sinafarokh
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When you add the wind to the airplane, shouldn't it be 20 degrees and 70 degrees, not 50 degrees and 20 degrees at 3:18

stacheyboy
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Please use HEADING instead of BEARING, as per the vectors drawn by U. As per your question 340 is the TAS [ almost equal to IAS
( as indicated by ASI), at low speeds and low altitudes], and one has been asked to find GS.

TAS is along HEADING whereas GS is along TC ( true course) represented by BEARING.
Anyways your presentation is quite helpful for students... 👍 from India.

babulsy
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I love this video but the mistakes kept bothering me

ceciliaollis
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Do we take the 90 off of the angle at the end every time no matter where it is or does the quadrant matter?

spencerfarrell
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In the beginning, there was nothing but Ather and its creator....

Brian McLogan

shanebarnes
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Why didn’t u find the square root of 372.23?

mohibhaque
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2 minute get the answer you spent almost 15 minutes and confused the viewers what a shame

chuckc