Related Rates (Lecture Part 1) What are they?

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This video is an excerpt from a Calculus 1 lecture in which the concept of Related Rates is introduced, and we work an example in which the sides of a cube are expanding, and we are asked to determine the rate at which the volume is expanding. We discuss how the rate of change of the length of the sides relates to the rate of change of the volume of the cube. We use implicit differentiation of the formula for the volume of a cube to find the relationship between these "related rates."
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Idolait Belony
Mac2311
An understanding I acquired from watching this video was that the pace of progress of volume, as for time, can be considered as "dv/dt". Your clarification of this model really explained what precisely was requested from us in each part and what precisely we needed to do to arrive at the right answers. Much thanks to you!! Amsome professor...

doebelony
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Sabrine Charles
MAC2311
The rate at which the volume of the cube is changing was found by relating its quantity to other given values.
Thank you for the video professor Hearn!

sermonsermon
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Thank you for the video, it was extremely helpful :)


MAC 2311
M-T 2:00-3:15
Tayla Thompson

“Ds/dt= Rate of change of length of side with respect to time, t sec.”

taylathompson
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Maxwell Jakus MAC2311 T/R 11:00 am - 1:15 pm
One important concept during the video was when you explained that even though it increases by one the other sides rate of change is different and varying.

maxwelljakus
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Cedric C
MAC2311
Related rates was always a consistent thorn in my side, but this video helped to clearly illustrate how to solve related rates problems

Blezerker
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1) Anthony M.
2) MAC1311 21Z
3). "ds/dt would be the rate of change of the length of the side, as compared to the change in time"

anthonym
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Gissell Morales
MAC2311
A part of the video that I found helpful was to start by calculating the volume of the cube.

gissellmorales
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Royce Lopez
MAC 2311
"What happens say the length of the side is four centimeters. What do we get for the volume then? 64." (Hearn, 1:42)

roylope
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alexander espinosa
MAC2311
i was surprised to find out that ds/dt can be found by looking at the question.

alexandermarcelo
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Stephania Grauer
MAC2311
One thing this video helped me review is what terms such as dv/dt stand for and how to use them. This will help me on the final.

stephaniagrauer
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Cesar Solari
MAC2311
A part of the video I found to be helpful was the graphic of the expanding cube at the beginning of the video. This small detail helped me visualize what the question was asking and helped me better interpret it.

cesarsolari
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Eric Haynes
MAC 2311
"ds/dt of change of length of side with respect to time, t sec." (Hearn 2:00-2:15)

rileyfreemang
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Michael Samuels
MAC 2311
Thank you for the video professor,


I am getting to understand when and how to use the terms such as dv/dt, with a little practice i should master it.

Learn--Code
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Rocky Rosado
MAC2311
"what we have here is now a relationship
between the rates so here we have on the left the rate at which the volume is changing and this is going to be equal to 3 times the length of the sides squared at that moment times the rate at which the side is changing" (Hearns 3:16-3:33)

usmcdd
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Mohammad Abid
MAC2311 M-R
"What we have here is now a relationship between the rates. So here we have on the left the rate at which the volume is changing and this is going to be equal to 3 times the length of the side squared at that moment times the rate at which the side is changing."

mohammadabid
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Vivica Simmons
MAC2311 M-R
"ds/dt would be the rate of change of the length of the side as compared to the change in time"

vsim
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Mitchell Thanath
MAC2311
"ds/dt, the rate at which 's' is changing"

mstriker
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Paul Chavez
MAC 2311 2pm-3:15pm m-r
"dv/dt is the rate of change of volume with respect of time"

paulchavez
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Casandra Sabillon
MAC2311
One thing I learned from this video that I think will help on my quiz is learning that ds/dt is the rate of change of length of side with respect to time, also known as t sec.

amatsuuz
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Eli Khashper
MAC2311
An insight I gained from watching this video was that the rate of change of volume, with respect to time, can be thought of as "dv/dt". Your explanation of this example truly helped clarify what exactly was asked of us in each part and what exactly we had to do to reach the correct answers. Thank you!!

elik