Find the Limit of sec(x) as x approaches negative pi/2 from the left

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Find the Limit of sec(x) as x approaches negative pi/2 from the left

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Technically, lim sec(x) (x < –π/2, x —> –π/2) does not exist. However, given x < –π/2, x —> –π/2 implies sec(x) —> –∞, insofar as this is just an abbreviation to say that for all real numbers B < 0, there exists some real number δ > 0, such that for all real numbers –δ < x + π/2 < 0, sec(x) > B.

angelmendez-rivera

Awesome explanation! I looked at the secant graph and I can also see it approached - infinity. What happens if was sec(x)^2?

DVKN

Cool. Interesting considerations with -infinity, +infinity and infinity. Consider a complex plane C has only one infinity, real numbers R has 2 infinities, but real numbers R is a subset of complex plane C. How come?

ivolva

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