How to find the remainder using modular exponentiation

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#mathematics #fermatlittletheorem #fermat
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I would've done it as (8-1)²⁰²⁴ + (8+1)²⁰²⁴ +1
Since odd terms will cancel out so we will get 8x2(sum of even terms ) + 2(1)²⁰²⁴ +1 hence the ans 3

silverfox
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3 answer it is very easy and can be done within 30 sec just by seeing
It is taught in binomial theorem and there are 2 methods 1by writing it like(8+1) type I don't like that but second one is you write 7^2024 as 49^1012 and divide and only write remainder😅

Tsarthak
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