Seek and Destroy JavaScript Free Code Camp

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[jacobhightower]

Hey, thanks for the help, I was stuck for a bit on this one for whatever reason, haha! I'm sure you already know by now, but for the last bit you could just type out: return placeholder.filter(Boolean); to achieve the same effect without going through an entire function! Edit: nvm, plenty of people have mentioned it already, haha! Keep up the good work!

[subhsamal]

Thank you buddy for your great explanation..I used from() to convert arguments into array. I was confused how to use filter(), you provided an awesome solution..

[TheWhatever]

thx man, you're literally my tutor ;)

[theodorep.]

I think this is the simplest solution:

function destroyer(arr) {


var args =

function check(i) {

return args.indexOf(i, 1)==-1;

}

var filtered = arr.filter(check);
return filtered;
}

[nezerworld]

Does anyone know as to why in the beginning it only returns the array instead of the entire string? If you're returning 'destroyer' shouldn't it return Everything in the ()?

[PastryFanatic]

Confused as to why the null values are created ...

[MatthewTaylorAu]

thanks for posting. yes, I found this difficult as well. Was very close to the same solution.
A few hangups I have.
- deleting an element from an array while looping through that array.
- the filter method - this still bothers me, I'm looking for more tutorials/exercises using filter. Also - equivalent methods in python and Java.

[anon]

thanks. your solutions make great sense for a beginner like me. Btw it still works without args.splice(0, 1) at line 4. why would arr.length and args.length have different values. trying to get that

[wantsoobaroo]

when does arr go from being [1, 2, 3, 1, 2, 3] to [1, null, null, 1, null, null]?
I tried commenting out portions of the answer and it seems like the for loops are causing this change but I don't know why that is.

edit: nevermind, figured it out. delete gets rid of the content of the element but keeps the element position; therefore, null is in its place.

[daviddume]

when you used .filter() you could easily write this: return arr.filter(Boolean);
So with that you could easily delete all 'null', because with Boolean you delete every variable of boolean type

[justinallen]

Could've just used placeHolder = arr.filter(Boolean); as the filter code. No need to write another function after that. Good job though!

[kouIShereNOfear]

Please have a look at this
function destroyer(arr) {
// Remove all the values
var args =
var filtering = args.splice(0, 1);
return arr.filter(function (element) {
return args.indexOf(element) === -1;
});
}

[mugrad]

that's way too much code and its confusing. I tried this and it worked

if(destroyer([1, 2, 3, 1, 2, 3], 2, 3)

function destroyer(arr) {

var mustRemove = [];
for(var i = 1; i < arguments.length; i++){
// arguments object to take additional arguments into account (2, 3)
}

var destroyer = []; //array that will eventually contain differing values

for(i = 0; i < arr.length; i++){ //looping through arr because we're checking this array for values belonging to the MR Array
if(mustRemove.indexOf(arr[i]) === -1){ //conditional statement to push unequal values into the destroyer array
destroyer.push(arr[i]);
}
}

return destroyer;


}

[Fred]

function destroyer(arr) {
const args = Array.from(arguments);
return arr.filter( val => args.indexOf(val) === -1);
}

destroyer([1, 2, 3, 1, 2, 3], 2, 3);

[AndressAndress]

My 2 methods of solving it :

// Method 1
function destroyer(arr) {
var args = Array.from(arguments);
args.splice(0, 1);
return arr.filter(function(val){
return args.indexOf(val) == -1
});
}

// Method 2
function destroyer(arr) {
arr1 = Array.from(arguments);
for (a=1;a<arr1.length;a++){
arr = number != arr1[a]
});
}return arr
}

[Rockygaming]

<script>
function destroyer(arr) {
for (var i=1;i<arguments.length;i++){
for (var j=0;j<arr.length;j++){
if (arr[j]===arguments[i]) arr.splice(j, 1);
}
}
return arr;
}

var result = destroyer([1, 2, 3, 1, 2, 3, 4, 5], 2, 3);
alert(result);
</script>

//This code working fine, but I want to dynamically pass values on destroyer(), means Take input box, in that i wrote [1, 2, 3, 1, 2, 3, 4, 5], 2, 3 then click the button output shown in alert.

[pablerdo]

Not using .filter:

function destroyer(arr) {
// Remove all the values
var args =
args.splice(0, 1);
var hola = [];
for(var i = 0; i < arr.length; i++){

hola.push(arr[i]);
}
}
return hola;
}

[VKBteamkiller]

OK, shorter version below...





function destroyer(ar){var ar.filter(x=>!a.includes(x))}

[VKBteamkiller]

Filter in action again! - below :-)





function destroyer(){var

[underRated]

function destroyer(arr) {
var args =
args.splice(0, 1);
for(var i =0 ; i<arr.length;i++){
for(var j=0;j<args.length;j++){
if(args[j]==arr[i]){
arr.splice(i, 1);
i--;
}
}
}
return arr;
}