January 2025 CSEC Mathematics Paper 2 Solutions & Tips

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📚 Welcome to Learning Maths with Duet!

17 Feb 2025

👉 Join me as I dive into the 2025 CSEC Mathematics Paper 2 and try to tackle these answers before anyone else!

🌟 Get ready to ace your CSEC Mathematics Paper 2 exam with our comprehensive answer guide! In this video, we'll walk you through the solutions to the 2025 paper, covering all the essential topics and question types. Whether you're a student looking to improve your math skills or a teacher seeking to supplement your lesson plans, this video is the perfect resource for you. Stay ahead of the curve and boost your confidence in math with our expert guidance. Watch now and get ready to succeed in your CSEC exam!

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january 2025 csec mathematics paper 2 solutions Online Learning,
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2025 cxc student tap in
we are all gonna pass

Misssunshine-xc
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I finally got the chance to study properly after months of sba and assignments even do its a month before I will pass🎉

Maxxiep-ws
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I love your explanation. You make this so easy. 🎉

OliverSquires-iv
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There is an error in question 4 part (c). You correctly used the gradient of the perpendicular bisector of CD but used point the D in your calculation. However, D is NOT on the perpendicular bisector so you should have used the midpoint of CD, (1, 4).

markmiller
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Very good video however I noticed a mistake in 4(c). For that part, you used the coordinates of point D to find the equation of the perpendicular bisector of CD. Point D does not lie on the perpendicular bisector; instead, you were to use the coordinates of the midpoint of CD since the perpendicular bisector passes through that point.

akielzy
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I hope this is cxc paper for this year

roshannawright
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Respect sir, very clear i already new most of the paper but thanks im advance

shertonthomas
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The median is the 20.5th mark which means it falls between the 20th and 21st scores. We then find the mean of the 20th and 21st scores.
Median = (7+8)/2
= 15/2
= 7.5

markmiller
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You have misread the question in 6(b) (ii).
The questions asks us to find the volume of the ENTIRE BLOCK OF CHEESE.

The ENTIRE BLOCK OF CHEESE IS CYLINDRICAL. You have found the volume of only one slice of cheese in the ENTIRE CYLINDRICAL BLOCK.

You need to find the number of equal slices of cheese in the cylindrical block of cheese.

Number of equal slices of cheese = 360^0 ÷ 18^0 = 20 slices

Volume of ENTIRE BLOCK OF CHEESE = volume of one slice × 20

markmiller
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I believe you did question 4c wrong as a Perpendicular Bisector cuts a line segment exactly in half (passes through the midpoint) and is perpendicular to the segment (forms a 90° angle).
Instead, you should have used the midpoint co-ordinate of the line CD (1, 4), instead of point D or even C in any case.
The correct answer should have been: y = 3x + 1

Edit: If you used the co-ordinate of point C or D, you would have not gotten the same equation for the Perpendicular line Bisector of CD

IAmBasedYxles
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hello could you explain how you got the 20 in i understand the -45 part in the velocity graph on part V

GetNub
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Hi sir i relly hope i get back a respond is this the cxc paper 2 what coming this year?

AmeliaCarthy-nf
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How did the 15 turn into 30 im lost at that part

RattBat-tx
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I'm lost when you put 30 at question 1 a.(i)

ValleryWilliams-im
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Sir for question 1 (ii) why it wasnt times 10 to the negative 2

MarioFerron-zv
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The median is 7.5, not 8 BTW u add the two middle number and divide it by 2 and the answer is 7.5

josettlawes
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