In figure, QR/QS = QT/PR and ∠ 1 = ∠ 2 Show that Δ PQS ~ Δ TQR | Q4 Exercise 6 3 class 10

Exercise 6.3 Question 4 Class 10
In figure, QR/QS = QT/PR and ∠ 1 = ∠ 2. Show that Δ PQS ~ Δ TQR.

HINT of Question 2 of Exercise 6.3 class 10:
Theorem 7.3: (class 9)
The sides opposite to equal angles of a triangle are equal.

Read it :
INTRODUCTION
Two figures are said to be congruent, if they have the same shape and the same size.
Two figures having the same shape (and not necessarily the same size) are called similar figures.
All congruent figures are similar but the similar figures need not be congruent.
Two polygons of the same number of sides are similar, if (i) their corresponding angles are equal and (ii) their corresponding sides are in the same ratio (or proportion)

Note📝
The above question is taken from NCERT class 10 chapter Triangles Exercise 6.3 Question 4

Practice :
Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point O. Using a similarity criterion for two triangles, show that OA/OC = OB/OD

Revise✍🏻:
Circles:

Real Numbers:

Polynomials

Quadratic Equation

Trigonometry

Connect with us 🤩:

#triangles #class10maths #ncert