Graph Theory 3: Hamiltonian Paths & Ore's Theorem

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Third mini-lecture in Graph Theory series.
  1. Math at Andrews University
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Комментарии
Автор

Again! What a wonderful lesson.
It's always this kind of lessons make me fall in love with math even when there's a math exam.

匿名者-qj
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If Ore's theorem is "D(U)+D(V)>=n ==> Hamiltonian circuit exists" then the converse is "Hamiltonian circuit exists ==> D(U)+D(V)>=n"? To disprove that shouldn't we provide an example of a graph with a Hamiltonian circuit for which D(U)+D(V)>/=n ? Your example is a graph with no Hamiltonian circuit, which is not what we need, right?

stuspivack
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Dear God. Please let me pass my oral exam about discrete mathematics tomorrow. Let my prayers be heard. Thank you, God. - A student

alexaviraghidvegi