Test Review of XL6009 DC to DC 1.2V to 32V 5A Buck Boost converter module

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In this video you will see Test Review of XL6009 DC to DC Buck Boost converter module

We have tested this module under different load, input and output voltage condition and result is presented.

View Section of this video:
00:00 Introduction
1:25 Data sheet
02:44 Voltage regulation stability

Boost conversion tests
-Input 12V, Output 30V, 4A at 06:48
-Input 12V, Output 30V, 3A at 07:20
-Input 12V, Output 24V, 4A at 07:43
-Input 12V, Output 24V, 3A at 08:05
-Input 12V, Output 24V, 2A at 08:18
-Input 12V, Output 24V, 1.5A at 08:43
-Input 12V, Output 24V, 1A at 09:11

Buck conversion tests
-Input 12V, Output 9V, 4A at 10:28
-Input 12V, Output 9V, 3A at 10:57
-Input 12V, Output 9V, 2A at 11:09
-Input 12V, Output 9V, 1.5A at 11:39
-Input 12V, Output 5V, 3A at 12:00
-Input 12V, Output 5V, 2A at 12:42
-Input 12V, Output 3.3V, 2A at 13:15

Tutorial by Ahmad Shamshiri form Canada
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The reviewer has misread the spec sheet. The 4 amp rating is for the switching MOSFET and essentially defines the Maximum INPUT current NOT the Maximum OUTPUT current. Consider that in the video's first load test he is trying to draw 4 amps at 30 volts from a 12 volt source. This is a 120 watt load. If we assume 92% efficiency that means we must draw 130 watts from the 12 volt source. This translates into aprox. 11 Amps.

This is well beyond the 4 Amp specification for the device. Because this is a buck-boost up converter the output current limit is derived from the input and output voltage. In the reviewer's example 12 Vin 30 Vout we can calculate the maximum current from this formula.

Iout = (4 Amps * Vin * 0.85%) / Vout

Note: I used 85% efficiency because the datasheet only gives a rating for one case and depending of the voltages it can range between 85% and 96%. Hence 85% is a safe maximum. In your specific use case, you may be able to exceed this slightly.

Simplifying our equation and inserting the values used in the video we get

Amps out = 3.4amps * Vin / Vout

3.4 *12/30 = 1.35 amps Maximum output at 30 Volts with and input source of 12 volts.

Note this formula is for any case where Vin < Vout.

spylake
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The XL series are actually quite successful when used for their own purposes. For example, in my tests on the buck converter, the efficiency is around % 75-80 for the LM2596, while it is around 90-95% for the XL4005. XL6009 is for boost converter only. I see that this circuit design including the Buck converter is actually a failed topology. You did a very nice and professional job. It was useful for me, thanks a lot!

manlot_
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Thankyou 11:11 this is what i needed. I have 12v 2A wall charger and want to convert it to 8v 2A. Going from 12 to 8. The aplication is for replacing 2 18650 Batteries with wall adapter.

danydepp
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These DC-DC converters with the XL6019E1 semiconductor in the TO263-5L package performs rather poorly, given the datasheet specifications.

However, the KeeYees DC-DC Boost Mini step-up converter with a micro USB input on the PCB which has the SDB628 6-pin SOT23 semiconductor package really outperforms the larger aforementioned units surprisingly well.

The entire KeeYees circuit board is less than 1/3 the size of the XL6019E1 type modules.

The SDB628 6-pin SOT23 component is a fraction of the size and it really outperforms the XL6019E1 by a landslide.

This seems very counterintuitive to say the least.

Thank you for this video and all of your research. Keep up the excellent work.

richgoza
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The stability test at 4.14 to 4.19 shows a nasty problem. If the input voltage drops below the minimum threshold - the output voltage jumps from the desired 8v up to 13.6v. My testing of an input supply drop-out - with a small LED load - has produced an over-voltage up to 25v when set for a 4v output. I would have expected the output to degrade safely when the input drops below the minimum.

sculpturekris
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If you read the data sheet for this buck boost converter it is rated at about 1 amp output continuous with about 10v differential so example 10volts in at 2 amps = 20volts out 1 amp = 22.5w input with losses about 2.5 watts 5a is its Max rating for milliseconds which includes input or output amperage

timbrown
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I purchased four of these and the slow boat from China just arrived. If I wanted to drive a white LED from a 1.2v cell how would I do it since this is not a CC driver?

generalawareness
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Seems to have two inductors. Is it an isolated buck / boost converter ?

neilparker
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Great review, very detailed and methodical. However I wish you also tested the efficiency of these things. They claim 94% efficiency in the datasheet. But with my actual test they had about 50% efficiency!!

puriap
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Does heatsink on the IC help on the temperature?

yubinator
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thank you sir you are so good Im Ali from Iraq 💖😊

عليعبدالكاظم-لط
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12V input and 30V - 4A output... How many Amps are you pulling from the INPUT ? 10 A ? ratings are given for the input, no ?

TheKetsa
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I want to get 12V 2.1 or 2.2 amp from this module as output voltage. Will it drop when the load is putted?

imrannazir
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Problem is with the charging capacitors, inductors and line path ampherage. Not with the topology...

niky
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Hi there, I ahve two questions.

1. Will adding heat sink to the IC help?

2. What buck/boost converter have you tested so far that you recommend.

Thank you in advance.

TaylorSoloaiJR
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I appreciate your work and demonstration. What a pity that you didn't measure the currents at 10V and 14V input and 12V output. I what to use this module to stabilize a battery. If you have that data, please let me know. Anyway thanks for the video.

pietdepad
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That FAILED message scared the shit out of me, man

Lann
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Question: Should you not adjust output voltage WHILE on the load instead ? Any 12v car battery will register 14.4-15v by itself and drop to 11-12v on load.

altamiradorable
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hey robojax I accidently cranked up or down the pot in the circuit. How do I fix it?

imperialrecker
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Sir can i run a 9volt 0.06amp wifi router with this module.use as a buck module from 12to 9volt?

sulaimankhan