LeetCode 242. Valid Anagram Solution Explained - Java

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Thanks. You are really good in algorithms..

babumon

I understand that char 'a' is the ACSII symbol whose value is 97, but how does this

for (int i = 0; i < s.length(); i++) {
characterCount[s.charAt(i) - 'a']++;

characterCount[t.charAt(i) - 'a']--;
}

check for anagrams? Why can't I use any other ACSII symbol char like 'b' or 'c'?

sheriffcrandy

Thank you Mr. White always appreciated

Kitchen-Raccoon

very clear and simple solution, thank you!

isaacli

Can we create StringBuilder for t and start removing one (only) character for each character in s. If StringBuilder is left with zero element then return true.

samj

I solved it by using two hashmaps and three for loops.... feeling so stupid after seeing this solution 😢

ritchievales

Hi, when I saw the solution, at first I did not get it until I watched your solution
I solved it with HasMap run time and memory was too high

billynader

Still confused about the char_count[s.charAt(i)-'a'] and the char_count[t.charAt(i)-'a'];

shiyangnie

Well one of the easiest solution i came across thank you.

syed_

Thank you, my friend. That's what I need now to survive.

maksymr.

Very help full I wish I could support you more than I can

sachitdalwadi

Starting your video with "this is one of the easiest problems, " tends to be a bit of a turn off. If the problem was easy for your viewers we would not be viewing your tutorial.

philbowden

would a hashmap be more or less efficient?

debdijmazumder

Sort them and check if they are equal or not

kathaigal

the code showing wrong answer when you check for the input rat and car

ronyEdits

("Hello", "hello") leads to indexOutOfBoundsException. The capital 'H' is the issue here.

ericsodt

I tried using Hashmap but got me 24ms, time complexity I beleive was O(m+n). that is the best I could do if this is a interview question...LoL. Never would have come up with this solution.

zihaoyan

Why dont sort both strings and compare if they both r same ..return true if it is else false

Impromptu

Good solution bad explanation. Where's my Indian guy explaining iteration at?

sanchit

i think you should have submit the code to see all testcase passed or not

lokanadhamc

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