☑️14 - Mesh Analysis with Voltage Sources

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In this lesson, we shall learn how to solve circuits problem using mesh analysis considering circuits with voltage sources.
A loop is any closed path in a circuit, while
A mesh is a loop that does not contain any other loop within itself.
The current in a mesh is called a mesh current

In this lesson we shall solve two examples.
Steps to solve circuits using mesh analysis
1. Assign mesh currents in the circuit
2. Apply kvl at each mesh and use ohms law to express the voltages in terms of mesh currents.
3. Solve the equations obtained simultaneously, if the equations obtained are more than two, it is preferred to use cramer's rule or matrix inversion method while you can use method of elimination and substitution for two equations.
NB: the number of meshes gives an indication of the number of equations you are going to obtain.

00:00 - Mesh Analysis
03:31 - Example 1
11:05 - Example 2

Playlists on various Course
1. Applied Electricity

2. Linear Algebra / Math 151

3. Basic Mechanics

4. Calculus with Analysis / Calculus 1 / Math 152

5. Differential Equations / Math 251

6. Electric Circuit Theory / Circuit Design

Make sure to watch till the end.
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Thank you.
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How do i know when to divide the equation and what no number to use

thatschemistry
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what is the name of the book so i can solve more problems ?

ahmadwehbi
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I didn't know you also have electrical analysis tutorials oh 🥹 this channel is enough to save a semester 😅🥹

BlessingsKanyika-vx
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In example 1, how do you solve for the voltages of each resistors then?

CL-sqbs
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In the example 1? Where did you get the 6 to divide 36?

LeandrieBermudo
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but the first example its seems to be 36= -2i1 -12(i1-i2) - 4i1 since resistance always resist the flow of current. Furthermore the current is entering from the positive terminal of the resistance and move out to the negative terminal thats why it should be negative

idrisabdullahi
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There is a mistake in example mesh 2, you did KVL with the current is for voltage

Kidvini
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may i ask in example 2 why did you on mesh 1 20=voltage drops isnt it 20-4(i1-i3)-2(i1-i2)=0 ??? please reply

yahboi
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sir can i ask if why does 2(i1) is positive if the polarity is + to - = negative?
Can you explain me why sir?

Mcsfastgaming
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Could you please tell me why in mesh no 2
You but (-12 ×(i1-i2) I think should +12×(i2-i1)
Thanks

hamzaatheb
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What difference does it make if I° is given and we have to find v° ???

PrettyCharm_MFAHH
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in second example 10 i0 shouldn't be negative at second mesh?

RayanSahib-zh
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Could you please explain the 1st example, current is zero in second loop, how's it possible. (Sorry for my English)

nitiponsupanitinun
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in example 2 how did you determine i3= d3/d ?

rickp
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but in example 2 you have i3=I_0, not i3=i0, how can you substitute it? uppercase I 0 is not the same as lowercase i0, isn't it?

ДіанаПастушенко
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Why I0 = i3 and equal i0, I can’t figure out 16:41

jerrychen
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Hy sir where can i send a question that i have im writing soon😢

ndzalamankwinika
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For the first example the mesh 1 how did u get the 4 ohms to have the current of I1 while the 12 ohms the current is (I1-I2)

KafuKemeh
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you made fail bro, the questions there were literally the same smh...

MIS