Differentiation Ex.1.5 Part 16 Maths-II 12th New Syllabus 2021| Higher Order Derivatives| Dinesh Sir

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Prof. Dineshkumar S. Gupta
(M.Sc., M.A.Ed, B.Ed., NET, PET, DSM, DSAG)

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But sir I have one doubt in q.2.3 .
I tried to solve it ..but the answer is not matching with your answer ..mine answer is 0

Explanation:-


d²y/dx²=3(2sin®×cos®)×1/cos®
d²y/dx²=3sin2®×1/cos®
[d²y/dx²]®=π/2 =3sin(π) ×1/cos(π/2)
d²y/dx²= 0

...plzz sir resolve the confusion..

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