Prove that 1/(tan3A-tana)-1/(cot3A-cotA) = cot2A

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prove that: (1 / tan3A - tanA) - (1 / cot3A - cotA) = cot2A

(1 / tan3A - tanA) - (1 / cot3A - cotA) = cot2A

1/tan3A-tanA-1/cot3A-cotA=cot2A​
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